Question

The mass of a nucleus is 0.042 amu less than the sum of the masses of 3 protons and 4 neutrons. The binding energy per nucleon in 7 3Li is:
5.6 Mev
10 Mev
13 Mev
39 Mev

Answer 1

The answer is 10 mev.                                           hope this helps

Answer 2

Answer: 5.6 Mev

Explanation: Binding energy is calculated by using the formula,

bonding energy = mass defect x 931 Mev

mass defect is given as 0.042 amu.

So, binding energy = 0.042 x 931 Mev = 39.012 Mev

Sum of protons and neutrons is known as number of nucleons. Li has 3 protons and 4 neutrons.

So, number of nucleons = 3+4 = 7

Binding energy per nucleon = $\frac{39.102Mev}{7}$

binding energy per nucleon = 5.6 Mev

So, the binding energy per nucleon for Li is 5.6 Mev where Mev stands mega electron volt.