Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.
I believe the answer is the first option. 1 to 3 with intervals of 1.
Hope this helps!
Answer:
<h2>1. subtract 3x, subtract 4, divide by -4</h2><h2 /><h2>2. add x</h2>
Step-by-step explanation:
1 + 3x = -x + 4.
subtract 3x
1 = -4x + 4
subtract 4
-3 = -4x
divide by -4
(-3)/(-4) = (4x)/(-4) ⇌ x = 3/4
-x + 6 = 5 - 3x
subtract 5
-x + 1 = - 3x
add x
1 = -2x
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355