12. 12m / 1 sec =12•30s=360 total tance he travels was 360 Miles
Answer: B. 23 inches to the left
Explanation: A vector quantity involves both magnitude and direction.
Answer:
The car overtakes the truck at a distance d = 3266.2ft from the starting point
Explanation:
Problem Analysis
When car catches truck:
dc = dt = d
dc: car displacement
dt: truck displacement
tc = tt = t
tc: car time
tt : truck time
car kinematics :
car moves with uniformly accelerated movement:
d = vi*t + (1/2)a*t²
vi = 0 : initial speed
d = (1/2)*a*t² Equation (1)
Truck kinematics:
Truck moves with constant speed:
d = v*t Equation (2)
Data
We know that the acceleration of the car is 3.00 ft / s² and the speed of the truck is 70.0 ft / s .
Development problem
Since the distance traveled by the car is equal to the distance traveled by the truck and the time elapsed is the same for both, then we equate equations (1 ) and (2)
Equation (1) = Equation (2)
(1/2)*a*t² = v*t
(1/2)*3*t² = 70*t (We divide both sides by t)
1.5*t = 70
t = 70 ÷ 1.5
t = 46.66 s
We replace t = 46.66 s in equation (2) to calculate d:
d = 70*46.66 = 3266.2ft
d = 3266.2 ft
Answer:
Explanation:
As we know that the motion of the balls with respect to the position of center of mass is pure rotational motion
so here we can find the position of center of mass with respect to ball B as
also we know that the velocity of the center of mass is given as
now relative velocity of ball B with respect to center of mass is given as
now tension in the string is given as
Recall that average velocity is equal to change in position over a given time interval,
so that the <em>x</em>-component of is
and its <em>y</em>-component is
Solve for and , which are the <em>x</em>- and <em>y</em>-components of the copter's position vector after <em>t</em> = 1.60 s.
Note that I'm reading the given details as
so if any of these are incorrect, you should make the appropriate adjustments to the work above.