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Anna35 [415]
2 years ago
15

5. How far can a car travel in 14 hours while going at a speed of 75 miles per hour?

Physics
2 answers:
Gemiola [76]2 years ago
5 0

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

Speed of the car is 75 miles per hour and it travels for 14 hours. so the distance travelled by it in the given period of time can be calculated using this formula ~

\qquad \sf  \dashrightarrow \: d = v \sdot t

\qquad \sf  \dashrightarrow \: d = 75 \times 14

\qquad \sf  \dashrightarrow \: d = 1050 \:  \: miles

so, it can travel 1050 miles in 14 hours

weeeeeb [17]2 years ago
3 0

Answer:

1050 miles

Explanation:

Simply:

d =  75 m/hr   *  14 hr   =1050 miles

 ( see how the 'hr' cancels and you are left with miles ?)

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History

Explanation:

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3 years ago
Reaction rates are affected by reactant concentrations and temperature. this is accounted for by the ________.
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7 0
3 years ago
In one cycle, a heat engine takes in 1000 J of heat from a high-temperature reservoir, releases 600 J of heat to a lower-tempera
Talja [164]

Answer:

η = 40 %  

Explanation:

Given that

Qa ,Heat addition= 1000  J

Qr,Heat rejection= 600 J

Work done ,W= 400 J

We know that ,efficiency of a engine given as

\eta=\dfrac{W(net)}{Q(heat\ addition)}

Now by putting the values in the above equation ,then we get

\eta=\dfrac{400}{1000}

η = 0.4

The efficiency in percentage is given as

η = 0.4  x 100 %

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Therefore the answer will be 40%.

4 0
3 years ago
Kelli weighs 440 N, and she is sitting on a playground swing that hangs 0.41 m above the ground. Her mom pulls the swing back an
kifflom [539]

Answer:

Explanation:

Initial height from the ground = .41 m

Final height = 1m

Height by which Kelli was raised ( h )= .59 m

When she passes through the lowest point , she loses P E

= mgh

= 440 x .59

= 259.6 J

kinetic energy possessed by her

= 1/2 mv²

= .5 x (440/9.8) x 2²

= 89.8 J

Difference of energy is lost due to work by  air friction

work done by  friction = 89.8 - 259.6

= - 169.8 J

4 0
3 years ago
A circular loop with radius r is rotating with constant angular velocity ω in a uniform electric field with magnitude E. The axi
inn [45]

Answer:

\Phi_{E} = E\pi r^2 \omega t

Explanation:

The electric flux is defined as the multiple of electric field and the area that the electric field passes through, such that

\Phi_{E} = \vec{E}\vec{A}

When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.

The above formula can be rewritten as follows

\Phi_{E} = EA\cos(\theta)

where θ is the angle between the electric field and the area of the loop. Note that, the direction of the area of the loop is perpendicular to the plane of the loop.

If the loop is rotating with constant angular velocity ω, then the angle can be written as follows

\theta = \omega t

At t = 0, cos(0) = 1 and the electric flux through the loop is at its maximum value.

Therefore the electric flux can be written as a function of time

\Phi_{E} = E\pi r^2 \omega t

3 0
3 years ago
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