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Anna35 [415]
1 year ago
15

5. How far can a car travel in 14 hours while going at a speed of 75 miles per hour?

Physics
2 answers:
Gemiola [76]1 year ago
5 0

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

Speed of the car is 75 miles per hour and it travels for 14 hours. so the distance travelled by it in the given period of time can be calculated using this formula ~

\qquad \sf  \dashrightarrow \: d = v \sdot t

\qquad \sf  \dashrightarrow \: d = 75 \times 14

\qquad \sf  \dashrightarrow \: d = 1050 \:  \: miles

so, it can travel 1050 miles in 14 hours

weeeeeb [17]1 year ago
3 0

Answer:

1050 miles

Explanation:

Simply:

d =  75 m/hr   *  14 hr   =1050 miles

 ( see how the 'hr' cancels and you are left with miles ?)

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An atom that no longer has a neutral charge is called an ion

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2 years ago
Is constant velocity same as constant acceleration?​
irakobra [83]

Answer:

No

Explanation:

constant velocity means zero acceleration because acceleration is rate of change of velocity. So when velocity remains constant there would be no acceleration.

in case of constant acceleration it means that velocity changes but with some consistent (same) amount each time. For example some object falling from tower, Velocity of the object will change(increases) by 9.8m/s for each second due to gravity of Earth. In this case there is change in velocity each second but with some consistent amount that is 9.8m/s.

7 0
2 years ago
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What is the net force acting on Hector and the toboggan?
prohojiy [21]

Answer:

C.490N

Explanation:

7 0
2 years ago
herical piece of candy is suspended in flowing water. The candy has a density of 1950 kg/m3 and has a 1.0 cm diameter. The water
ki77a [65]

Answer: Below is the complete question

A spherical piece of candy is suspended in flowing water. The candy has a density of 1950 kg/m3 and has a 1.0 cm diameter. The water velocity is 1.0 m/s, the water density is assumed to be 1000.0 kg/m3, and the water viscosity is 1.0x10-3 kg/m/s. The diffusion coefficient of the candy solute in water is 2.0x10-9 m2/s, and the solubility of the candy solute in water is 2.0 kg/m3. Calculate the mass transfer coefficient (m/s)

answer:

mass transfer coefficient = 9.56 * 10^-5 m/s

Explanation:

Candy density = 1950 kg/m^3

Candy diameter = 1 cm

Velocity of water = 1 m/s

water density = 1000 kg/m^3

Viscosity of water = 1 * 10^-3 kg/m/s

diffusion coefficient of candy in water = 2 * 10^-9 m^2/s

solubility of candy = 2 kg/m^3

<u>Determine the mass transfer coefficient ( m/s ) </u>

( Sh) mass transfer coefficient ( flow across sphere ) = 2 + 0.6Re^1/2 * SC^1/3

where : Re = vdp / μ ,   Sh = KLd / Deff

attached below is the remaining solution .

mass transfer coefficient =  9.56 * 10^-5 m/s

6 0
2 years ago
Two satellites A and B of the same mass are orbiting Earth in concentric orbits. The distance of satellite B from Earth’s center
riadik2000 [5.3K]

Answer:

ratio of tangential velocity of satellite b and a will be 0.707

Explanation:

We have given distance of satellite B from satellite A is twice

So r_b=2r_a

Tangential speed of the satellite is given by

v=\sqrt{\frac{GM}{r}}, G is gravitational constant. M is mass of satellite and r is distance from the earth

We have to find the ratio of tangential velocities of b and a

From the relation we can see that tangential velocity is inversely proportional to square root of distance from earth

So \frac{v_b}{v_a}=\sqrt{\frac{r_a}{r_b}}

\frac{v_b}{v_a}=\sqrt{\frac{r_a}{2r_a}}

\frac{v_b}{v_a}=\sqrt{\frac{1}{2}}

\frac{v_b}{v_a}=0.707

So ratio of tangential velocity of satellite b and a will be 0.707

5 0
3 years ago
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