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masya89 [10]
4 years ago
14

The term time dilation refers to which effect?

Physics
2 answers:
RoseWind [281]4 years ago
6 0
Is the apparent loss of time of a moving clock as observed by a stationary observer. Thats what i think.
Strike441 [17]4 years ago
6 0
<span>In the theory of relativity, time dilation is a difference of elapsed time between two events as measured by observers either moving relative to each other or differently situated from a gravitational mass or masses.</span>
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Which of the following choices is the best example of potential energy?
jekas [21]

Answer:

A basketball sitting still in a players hands

Explanation:

The other 3 answers have the ball <u>in motion</u> (going towards the basket, bouncing, and rolling) so that would be <u>kinetic energy</u>.

When the basketball is sitting in the player's hands, it has the potential to be in motion.

8 0
3 years ago
Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m ea
madreJ [45]
In order to answer this exercise you need to use the formulas

 S = Vo*t + (1/2)*a*t^2

Vf = Vo + at

The data will be given as

Vf = final velocity = ?

Vo = initial velocity = 1.4 m/s

a = acceleration = 0.20 m/s^2

s = displacement = 100m

And now you do the following:

100 = 1.4t + (1/2)*0.2*t^2

t = 25.388s

and

Vf = 1.4 + 0.2(25.388)

Vf = 6.5 m/s

So the answer you are looking for is 6.5 m/s
7 0
3 years ago
Read 2 more answers
According to the work equation, if you want to increase the distance on the
natka813 [3]
I think the answer is B because I did this before
7 0
3 years ago
Which two of the following reduce the background noise in magneto- medicine?
horrorfan [7]

Answer:

The answer is b.) and d.)

Explanation:

The options to reduce the background noise in magneto-medicine are given as follows:

a.) Orienting the heart parallel to the Earth's field

   - This will have no significant effect on the measurements.

b.) Taking the difference of two nearby sensor measurements (gradiometer).

    -This answer is TRUE.

c.) Placing the heart in a perpendicular fashion to the Earth's magnetic field.

   _ This answer also will not have any significant effect on measurements.

d.) Using physical means to shield environmental fields.

   - This answer is TRUE.

4 0
3 years ago
A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial veloci
JulijaS [17]

Answer:

t = T/4

Explanation:

The power delivered to the mass by the spring is work done by the spring per second.

P = \frac{dW}{dt}

The work done by the spring is equal to the elastic potential energy stored in the spring.

U = \frac{1}{2}kx^2

The maximum energy stored in the spring is at the amplitude of the oscillation.

U_{max} =\frac{1}{2}kA^2

So the first time the mass reaches to its amplitude can be found by the following equation of motion:

x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)

When the mass reaches the amplitude:

A = A\cos(\omega t + \pi/2)\\1 = \cos(\omega t + \pi/2)\\\omega t + \pi/2 = \pi

because cos(π) = 1.

\omega t = \pi/2

Using ω = 2π/T,

\omega t = \pi/2\\\frac{2\pi}{T}t = \pi/2\\t = \frac{T}{4}

4 0
4 years ago
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