All categories

4 years ago

The term time dilation refers to which effect?

Physics

2 answers:

RoseWind [281]4 years ago

6 0

Is the apparent loss of time of a moving clock as observed by a stationary observer. Thats what i think.

Strike441 [17]4 years ago

6 0

<span>In the theory of relativity, time dilation is a difference of elapsed time between two events as measured by observers either moving relative to each other or differently situated from a gravitational mass or masses.</span>

You might be interested in

How was Einstein's theory that energy and mass are interchangeable eventually proven to be correct?

Pani-rosa [81]

Answer:

Stanley Eddington confirmed the theory by his observations and inferences using the solar eclipse

Explanation:

Albert Einstein proposed a theory that energy and mass are interchangeable; termed the theory of special relativity. This can be observed when an object moves with the speed of light. The theory states that all laws in physics are the same for all non-accelerating observers.

Thus,

E = m $c^{2$

This theory could not be proven over many years, therefore it was not fully accepted.

In 1919, Stanley Eddington confirmed the theory by his observations and inferences using solar eclipse. The theory is now very accurate at any given speed when gravitational force tends to zero. This has lead to other observations to prove Einstein's theory.

8 0

3 years ago

Mountain pull. A large mountain can slightly affect the direction of ""down"" as determined by a plumb line. Assume that we can

Nastasia [14]

Answer:

6.18 um

Explanation:

The plumb line will be pulled down by a combination of the gravitationall pull of Earth and of the mountain. The Earth pulls down and the mountain to the side. Because of this it will fall not in a straight line down, but slightly to the side. Since the plumb line will follow the compound gravity we can imagine a rectangle triangle formed by the plumb line, a vertical line that ends at the same height as the plumb line, and the sideways displacement.

The total gravity will be proportional to the plumb line lenght, the vertical line will be proportional to Earth's gravity and the sideways displacement to the mountain pull.

The gravity of Earth is 9.81 m/s^2

The pull of the mountain will be defined by Newton's law of universal gravitation:

$F = G \frac{m1 * m2}{r^2}$

Where

F: pull force

G: universal gravitational constant (6.67e-11 m^3/(kg * s)

m1: mass of the mountain

m2: mass of the plumb

r: distance between mountain and plumb (3 km in this case)

If we divide both sides by m2 we obtain the acceleration towards the mountain of the plumb

$a = G \frac{m1}{r^2}$

Now we need the mass of the mountain. This will be its volume times it's density. The volume depends on the radius (since we consider it as a sphere)

$m1 = \delta * \frac{4}{3} * \pi * r^3$

$m1 = 2.6e3 * \frac{4}{3} * \pi * 1000^3 = 1.09e13 kg$

So, the acceleration on the plumb will be

$a = 6.67e-11 \frac{1.09e13}{3000^2} = 8.08e-5 m/s^2$

This is very small compared to the pull of Earth, so we can make an approximation that the length of the plumb line is equal to vertical line.

We can use the principle of similar triangles to say that:

$\frac{\Delta x}{L} = \frac{a}{g}$

So:

$\Delta x = \frac{a * L}{g} = \frac{8.08e-5 * 0.75}{9.81} = 6.18e-6 m = 6.18 um$

3 0

3 years ago

A bicyclist rides 1.86 km due east, while the resistive force from the air has a magnitude of 5.12 N and points due west. The ri

Llana [10]

Answer:

-19.0 kJ

Explanation:

Let's keep in mind that the direction of the resistive force is always opposite to the displacement of the bicyclist.

- In the first part of the ride:

Displacement: d = 1.86 km = 1860 m

Resistive force: F = 5.12 N

Angle between the direction of the force and the displacement: $\theta=180^{\circ}$

So, the work done by the resistive force is

$W=Fdcos \theta =(5.12 N)(1860 m)(cos 180^{\circ})=-9523 J$

- Similarly, in the second part of the ride:

Displacement: d = 1.86 km = 1860 m

Resistive force: F = 5.12 N

Angle between the direction of the force and the displacement: $\theta=180^{\circ}$

So, the work done by the resistive force is

$W=Fdcos \theta =(5.12 N)(1860 m)(cos 180^{\circ})=-9523 J$

Therefore, the total work done by the resistive force during the round trip is

$W=-9523 J+(-9523 J)=-19046 J=-19.0 kJ$

3 0

4 years ago

A remote control car is traveling at a velocity of 0.50 m/s when it hits a wall and comes to a stop in 0.050 seconds. What is th

OlgaM077 [116]

Answer:0.50m/s divide by 0.050sec = 10m/s

Explanation: dividing the meter per second [m/s] by the second [s

7 0

4 years ago

When Stone B collides with Stone A during Test 2, Stone B stops and Stone A begins to move. Which statement BEST describes the m

Anna11 [10]

Answer:

Explanation:

According to law of conservation of momentum, the total momentual in the system will be conserved

5 0

2 years ago