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zhuklara [117]
2 years ago
7

A cart is uniformly decelerating from rest. The net force acting on the cart is

Physics
1 answer:
mina [271]2 years ago
7 0

Answer:

i think the answer is constant

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A high diver dives into a swimming pool. His potential energy at the top is 10,000 J (relative to the surface of the pool). What
Semmy [17]

Answer:

Kinetic energy of diver at 90% of the distance to the water is 9000 J

Explanation:

Let d is the distance between the position of the diver and surface of the pool.

Initially, the diver is at rest and only have potential energy which is equal to 10000 J.

As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.

Energy before diving = Energy during diving

(Potential Energy + Kinetic Energy) =  (Kinetic Energy +  Potential Energy)

When the diver reaches 90% of the distance to the water, its kinetic energy

is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,

K.E. = \frac{90}{100}\times10000

K.E. = 9000 J

6 0
2 years ago
Why might it be important to know your inherited traits passed down by your parents?
ExtremeBDS [4]

Answer:

health factors that could harm you or your offspring

3 0
2 years ago
Which of the following is the human ear able to detect?
DaniilM [7]
I believe it would be a musical note
7 0
2 years ago
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Please help!!~
lisov135 [29]

Answer:

C. Waves transfer energy, but not matter.

Explanation: hope this helps :)

7 0
2 years ago
a man drags a 8.10 kg bag of mulch at a constant speed, applying a 29.5 N at 38°. what is the coefficient of friction?​
lesantik [10]

Answer:

The coefficient of friction is 0.38.

Explanation:

The free body diagram is drawn below.

Let f be frictional force acting in the backward direction as shown. Let the coefficient of friction be \mu. Let N be the normal reaction force acting on the bag.

Given:

Mass of the bag is, m=8.10\textrm{ kg}

Force acting at \theta = 38° is F= 29.5\textrm{ N}

Acceleration due to gravity is, g=9.8\textrm{ }m/s^{2}

The force F can be resolved into its components as F_{x}=F \cos \theta and F_{y}=F \sin \theta

Therefore,

F_{x}=29.5\cos(38)=23.25\textrm{ N}\\F_{y}=29.5\sin(38)=18.16\textrm{ N}

Now, as there is no acceleration in vertical direction, therefore,

Sum of upward forces = Sum of downward forces

N+F_{y}=mg\\N=mg-F_{y}=8.10\times 9.8-18.16\\N=79.38-18.16=61.22\textrm{ N}

Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.

Therefore, backward force = forward force.

f=F_{x}\\f=23.25\textrm{ N}

Now, frictional force is given as:

f=\mu N\\\mu = \frac{f}{N}=\frac{23.25}{61.22}=0.38

Therefore, the coefficient of friction is 0.38.

8 0
3 years ago
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