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3 years ago

A cart is uniformly decelerating from rest. The net force acting on the cart is

Physics

1 answer:

mina [271]3 years ago

7 0

Answer:

i think the answer is constant

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Simplifying fractions<br>30 over 54

Veronika [31]

Answer:

5/9

Explanation:

First, find a common factor for 30 and 54.

30 and 54 can both be divided by 2.

30 divided by 2 = 15

54 divided by 2 = 27

So, your new fraction is 15/27.

However, don't stop there.

15 and 27 can both be divided by 3 as well.

15 divided by 3 = 5

27 divided by 3 = 9

So, your final answer is 5/9.

I hope this helps! :)

4 0

3 years ago

Read 2 more answers

What is the speed of a bobsled whose distance-time graph indicates that it traveled 123m in 28s?

Irina18 [472]

4.39 seconds per meter

6 0

3 years ago

You need to design a 60.0-Hz ac generator that has a maximum emf of 5500 V. The generator is to contain a 150-turn coil that has

olchik [2.2K]

Answer:

So magnetic field will be equal to 0.1144 T

Explanation:

We have given frequency f = 60 Hz

Maximum emf e = 5500 volt

Number of turns N = 150

Area $A=0.85m^2$

Emf generated in ac generator is given $e=NBA\omega sin(\omega t)$

For maximum emf $sin(\omega t)=1$

So maximum emf will be equal to $e=NBA\omega$

$B=\frac{e}{NA\omega }=\frac{5500}{150\times 2\times 3.14\times 60\times 0.85}=0.1144T$

So magnetic field will be equal to 0.1144 T

3 0

3 years ago

If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular co

sergij07 [2.7K]

Answer:

Angular velocity, $\omega=35.36\ rad/s$

Explanation:

It is given that,

Maximum emf generated in the coil, $\epsilon=20\ V$

Diameter of the coil, d = 40 cm

Radius of the coil, r = 20 cm = 0.2 m

Number of turns in the coil, N = 500

Magnetic field in the coil, $B=9\times 10^{-3}\ T$

The angle between the area vector and the magnet field vector varies from 0 to 2 π radians. The formula for the maximum emf generated in the coil is given by :

$\epsilon=NBA\omega$

$\omega=\dfrac{\epsilon}{NBA}$

$\omega=\dfrac{20\ V}{500\times 9\times 10^{-3}\ T\times \pi (0.2\ m)^2}$

$\omega=35.36\ rad/s$

So, the angular velocity of the circular coil is 35.36 rad/s. Hence, this is the required solution.

6 0

3 years ago

I’ll give brainliest!! please help and answer correctly! plsss answer quick

noname [10]

Answer:

i dont think anything will happen so maybe A: the wall is larger than you.

Explanation:

8 0

3 years ago