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Maksim231197 [3]
3 years ago
11

Please help me answer this math question 1/2(b-12)

Mathematics
2 answers:
Sever21 [200]3 years ago
4 0

we have given an equation 1/2(b-12)

we need to simplify the given equation.

the distributive property is used here a(b+c)=ab+ac

1/2(b-12)=\frac{b}{12} -\frac{12}{2}

if we simplify the terms

we get \frac{b}{2} -\frac{6}{1}.

Digiron [165]3 years ago
3 0

1 / 2 (b - 12) ===> b / 2 - 6

Steps:

1 / 2 (b - 12)

Apply the Distributive Law: a ( b - c ) ===> ab - ac

a ===> 1 / 2; b ===> b; c ====> 12

1 / 2 b - 1 / 2 * 12

1 / 2 b - 12 * 1 / 2

Simplify:

1 / 2 b - 12 * 1 / 2

b / 2 - 6

1 / 2 b - 12 * 1 / 2

1 / 2 b ===> b / 2 ===> 1 / 2 b

Multiply Fractions:

a ( b ) / c ===> a( b )/c

1 * b / 2

Multiply:

1 * b ===> b

b / 2

12 * 1 / 2 ===> 6

12 * 1 / 2

Multiply Fractions::

a ( b ) / c =====> a(b)/c

1(12)/2

Multiply the numbers:

1 * 12 =====> 12

12 / 2

Divide numbers:

12 / 2 ======> 6

6

Answer: b / 2 - 6

Therefore, 1 / 2 ( b - 12 ) =========> b / 2 - 6

Hope that helps!!!!! : )

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You measure the lifetime of a random sample of 25 rats that are exposed to 10 Sv of radiation (the equivalent of 1000 REM), for
Slav-nsk [51]

Answer:

CI 95%(μ)= [13.506 ; 14.094]

Step-by-step explanation:

The confidence interval (CI) formula is:

CI (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proportion of the distribution tails that are outside the confidence interval. In this case, 5% because 100-90%

Z(5%/2)= is the critical value of the standardized normal distribution. In this case is 1.96

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n= number of observations . In this case 25

Then, the confidence interval (90%) is:

CI 95%(μ)= 13.8+- [1.96*(0.75/sqrt(25)]

CI 95%(μ)= 13.8+- [1.96*(0.75/5) ]

CI 95%(μ)= 13.8+- (0.294)

CI 95%(μ)= [13.8-0.294 ; 13.8+0.294]

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