Sin(x+y)-sin(x-y)/cos(x+y)+cos(x-y)=tany how do i verify this?
1 answer:
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Answer:
Step-by-step explanation:
Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,
Rule to be followed,
A(x, y) → P(-y, x)
Therefore, A(1, 1) → P(-1, 1)
Similarly, B(3, 2) → Q(-2, 3)
C(2, 5) → R(-5, 2)
Triangle given in second quadrant will be the triangle PQR.
If the point P of triangle PQR is reflected across a line y = x,
Rule to be followed,
P(x, y) → X(y, x)
P(-1, 1) → X(1, -1)
Similarly, Q(-2, 3) → Y(3, -2)
R(-5, 2) → Z(2, -5)
Therefore, triangle given in fourth quadrant is triangle XYZ.
Given a point in coordinates form 
, one can compute the cartesian form like this:
We have:
We get the cartesian form then:
We have:
We get the cartesian form then:
Answer:
The solution of the given trigonometric equation
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given
<u><em>Step(ii)</em></u>:-
The solution of the given trigonometric equation
<u><em>verification </em></u>:-
put
Both are equal
∴The solution of the given trigonometric equation