Sin(x+y)-sin(x-y)/cos(x+y)+cos(x-y)=tany
how do i verify this?
1 answer:
Answer:
Step-by-step explanation:
Numerator
sin
x
cos
y
+
cos
x
sin
y
−
[
sin
x
cos
y
−
cos
x
sin
y
)
=
sin
x
cos
y
+
cos
x
sin
y
−
sin
x
cos
y
+
cos
x
sin
y
=
2
cos
x
sin
y
Denominator
cos
x
cos
y
−
sin
x
sin
y
+
cos
x
cos
y
+
sin
x
sin
y
=
cos
x
cos
y
−
sin
x
sin
y
+
cos
x
cos
y
+
sin
x
sin
y
=
2
cos
x
cos
y
---------------------------------------------------------------
left side can now be expressed as
2
cos
x
sin
y
2
cos
x
cos
y
=
2
cos
x
sin
y
2
cos
x
cos
y
=
sin
y
cos
y
and
sin
y
cos
y
=
tan
y
=
right side hence proved
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