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2 years ago

The diameter of a circle is 16 inches what is the radius of the circle?

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

6 0

Answer:

8 inches

Step-by-step explanation:

The diameter of a circle is two times the radius of the circle, and radius is half as long as the diameter of the same circle.

P.S., I'm not sure why the answers are in feet, they should be in inches!

Please mark Brainliest! :)

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Help me ...Given △ABC≅△EFG, which congruency statement is true?

MrRa [10]

Answer:

(C.) AC¯¯¯¯¯≅EG¯¯¯¯¯ is true

Step-by-step explanation:

The positions of the letters in naming the triangles in the statement of congruent tells you which sides are congruent.

△ABC≅△EFG

Sides AB and EF are congruent

△ABC≅△EFG

Sides BC and FG are congruent

△ABC≅△EFG

Sides AC and EG are congruent

Look at the choices:

(C.) AC¯¯¯¯¯≅EG¯¯¯¯¯ is true

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9 months ago

The sum of the angles of a triangle is Select one: a. 360 b. 180 c. 90 d. 60

e-lub [12.9K]

Answer: b. 180

Step-by-step explanation:

The sum of the angles of a triangle is 180°.

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2 years ago

Read 2 more answers

Can someone help with numbers 1 and 2 for both of them tell me the answer and how you get it

Pani-rosa [81]

Answer:

Here a = 20,, b= 8

Step-by-step explanation:

Using Pythagoras theorem,

a^2 + 15^2 = 25^2 ,, b^2 + 6^2 =10^2=100

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2 years ago

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1. Solve for y 4x + 2y = 6

xenn [34]

Answer:

y = -2x + 3

Step-by-step explanation:

4x + 2y = 6

⇔ 2y = $\frac{6 - 4x}{2} = \frac{6}{2} - \frac{4x}{2} = 3 - 2x = -2x + 3$

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2 years ago

Which equation can be solved by using this expression?

Marat540 [252]

Answer:

The correct answer option is B. 2 = 3x + 10x^2

Step-by-step explanation:

We are to determine whether which of the given equations in the answer options can be solved using the following expression:

$x=\frac{-3 \pm\sqrt{(3)^2+4(10)(2)} }{2(10)}$

Here, $a = 10, b = 3$ and $c=-2$ .

These requirements are fulfilled by the equation 4 which is:

$12=3x+10x^2$

Rearranging it to get:

$10x^2+3x-2=0$

Substituting these values of $a,b,c$ in the quadratic formula:

$x= \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

$x= \frac{-3 \pm\sqrt{(3)^2-4(10)(-2)} }{y}$

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2 years ago