11 pints equal 176 fluid ounces
Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
Answer:
Step-by-step explanation:
3) diameter of penny = 19 mm
r = 19/2 = 9.5 mm
Area of penny = πr²
= 3.14 * 9.5 * 9.5
= 283.385
= 283.39 mm²
Diameter of nickel = 21 mm
r = 21/2 = 10.5 mm
Area of nickel = πr²
= 3.14 * 10.5 *10.5
= 346.185
= 346.19 mm²
346.19 - 283.39 = 62.8 mm²
Area of Canadian nickel is greater than Canadian penny by 32.6 mm²
4) r = 12 mm
Area of circle = πr²
= 3.14 * 12 * 12
= 452.16 mm²
5) r = 20 cm
Area of circle = πr²
= 3.14 * 20 * 20
= 1256 cm²
Answer:
HI! I think the answer is 4.
Answer and Explanation:
<em>Solving 3x + 2y = 9 for y gives y = -(3/2)x + (9/2).
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