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Brut [27]
4 years ago
5

How do i solve 1/3h-4(2/3h-3) = 2/3h-6??

Mathematics
1 answer:
Vlad [161]4 years ago
3 0
1\3h-2.7+12=2\3h-6 -2.7+12+6=2\3h-1\3h 15.3=1\3h multiply both sides by 3 45.9=h
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A recursive rule for an arithmetic sequence is a1 = 4; an = an-1 + 3 . What is an explicit rule for this sequence? (Picture atta
Slav-nsk [51]
Answer: 3n+1
(no need to type in the "a_n" or "an" part, as it's already done)

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Explanation:

The first term is a1 = 4 since it is given to us
The common difference is d = 3. This is the value that we add to each term to get the next as the recursive steps shows when we write a(n) = a(n-1)+3
In other words,
nth term = [ (n-1)st term ] + 3
next term = (previous term) + 3

Using a1 = 4 and d = 3, we get the following
an = a1+d(n-1)
an = 4 + 3(n-1)
an = 4+3n-3
an = 3n + (4-3)
an = 3n+1
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Is there a picture to that question
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