Answer:
The lens
Step-by-step explanation:
The lens of the eye is a biconvex, transparent structure of the eye that helps in refraction along with the cornea.
Hope this helps!!
10, 20, 30, 40, 50, 60, 70, 80, 90, 100
Answer:


Step-by-step explanation:
Given




See comment for missing part of the question
Required
Complete the expression to determine the dimension of a rectangle
We have:

Open bracket

Equate to 0

Expand

Factorize

Factor out x + 2

Solve for x
or 
or 
The value of x cannot be negative
So:

Recall that:


So:

---- i.e. 5 - 3
Answer:
Step-by-step explanation:
<u>Given equation:</u>
<u>Solve:</u>
- 4/7 + 8/3
- = 12/21 + 56/21
- =

- = 3 5/21.
- = 68/21.