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vlada-n [284]
3 years ago
13

Tell weather each equation has one, zero, or infinitely many solutions. -(2x + 2) - 1 = -x - (x + 3)

Mathematics
1 answer:
Anestetic [448]3 years ago
7 0
-(2x+2)-1=-x-(x+3) \\
-2x-2-1=-x-x-3 \\
-2x-3=-2x-3 \\
0=0 \\
always \ true \\ \\
\boxed{\hbox{infinitely many solutions}}
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(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

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3 years ago
Jasmine divided her garden answer six equal parts she planted flowers and 56 of the garden how many parts of the whole garden th
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I think the answer is 9 with 2 remaining
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Is 6% of a pound weigh more than an ounce
Katena32 [7]
No, it doesn't.

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Based on the information given in the diagram, choose all of the statements that are correct.
kvv77 [185]

Answer:

i think its the last one

Step-by-step explanation:

i think its the last on ig

3 0
3 years ago
Please help I am on number 1 please explain
jeka57 [31]
A % is out of a hundred, so you don't need the %/100. Then, you wouldn't do cross multiplication, you would just divide 15/27. Remember, it would be 15/27  because it's percent markup, not the percent the price increased by. So, doing that simple calculation on a calculator you get 0.5555. This converted to a percent is just moving the decimal to the right twice, or multiplied by a 100. That would give you 55.55%, and that's your answer. Make sense?
5 0
3 years ago
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