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BlackZzzverrR [31]
4 years ago
5

Offering 20 points and Brainliest! What's the answers to these two questions?

Mathematics
1 answer:
anzhelika [568]4 years ago
8 0

Answer:

21:A 22:D

Step-by-step explanation:

hope that helps

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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
Solve -36 4/9-(-10 2/9)-(18 2/9)
LuckyWell [14K]

Answer:

negative 400 over 9−  

400

9

=negative 44 and 4 over 9− 44

4

9

≈negative 44.444−44.444

Step-by-step explanation:

3 0
3 years ago
1 3/5 x - 3/4 plz help thank you
lianna [129]
I hope this helps you

8 0
3 years ago
1). (6x-5)/(x^3-4x^2+3x-12)
Lisa [10]
I have attached all the graphs below. I below you cannot factor these down. You might just have to use the graphs to find the values of x. 

Hope I helped :) 

5 0
3 years ago
A carnival is selling red tickets for rides and yellow tickets for games. The red tickets are $1.25 each and the yellow tickets
FinnZ [79.3K]

Answer:

Your answer.

Equation is D

R = 622

Y = 410

Thank you. And give my answer as Brainlist answer. Follow me for more

Step-by-step explanation:

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