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3 years ago

What is the distance of the dog along the coordinate number line

Mathematics

1 answer:

Lelechka [254]3 years ago

4 0

Answer:

69420

Step-by-step explanation:

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Find the following measure for this figure.

miv72 [106K]

l=11
r=5

Now

LSA:-

πrl
π(11)(5)
55πunits ²

4 0

2 years ago

Please I need help it's really hard

Vitek1552 [10]

I'd say angle A = angle B
arc tangent (angle B) = 150 / 555
arc tangent (angle B) = 0.2702702703 
angle B = 15.124 degrees

By the way 555 feet is the height of the Washington Monument.

3 0

3 years ago

A chef makes a fruit salad using pears and mangos. Pears and mangos each cost $2.25 per fruit. The chef buys x pears and y mango

GrogVix [38]

Answer:

P=2.25x-----------1

M=2.25y----------2

Step-by-step explanation:

Step one:

given data

we are told that the cost of pears= $2.25 each

and cost of mango= $2.25 each

Step two:

the chef bought x pears and y mangoes

let the total cost of pears be P

and for mango be M

P=2.25x-----------1

M=2.25y----------2

3 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

A flower pot's base has six sides that are all the same length. Each side measures x - 6 units. The base's perimeter is 78 units

Nadusha1986 [10]

The answer would x=19 units

5 0

3 years ago

What is the distance of the dog along the coordinate number line​

What is the distance of the dog along the coordinate number line