9514 1404 393
Answer:
30°
Step-by-step explanation:
The relationship between triangle sides and angles can be remembered using the mnemonic SOH CAH TOA. Here, we're interested in the relationship involving the hypotenuse and the side opposite the angle:
Sin = Opposite/Hypotenuse
For a ramp 1 m high and 2 m long, we have ...
sin(x) = (1 m)/(2 m) = 1/2
x = arcsin(1/2) = 30°
The elevation angle of the ramp needs to be 30°.
B) should be your answer
The first one (the one given), is 6 "points" (forgot what it's called sorry) from 0 on all sides. To dilate it 1/3, divide 6 and 3
6/3 = 2
The one's that have points that land on points with 2 in it is B
so B is your best answer
hope this helps
Using the formula:
V= 1/6 πd^3
V ≈ 1838.78
1: cell
2: distinction
3: assumption
4: foliage
5: commision
6: viewpoint
7: considerable
8: membrane
9: cell
10: final
11: viewpoint
12: considerable
uwu
Edit: added 9-12 didn't see them until I accidentally scrolled down, lol.
Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
<u />
II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
