3 years ago

I really need help please!

1 answer:

5 0

Simple...

you have: $\frac{ 3^{-4}* 2^{3}* 3^{2} }{ 2^{4}* 3^{-3} }$

Multiply it out-->>

$\frac{8}{9}$ ÷ $\frac{16}{27}$

= $\frac{3}{2}$ (A)

Thus, your answer.

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Use the quadratic formula to solve x² + 9x + 10 = 0. What are the solutions to the equation?

jok3333 [9.3K]

Answer:

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Step-by-step explanation:

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

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$x^2+9x+10=0$

Plug in values:

$x=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

First value of x:

$x=\frac{-9+\sqrt{41}}{2}=-1.30$ (2 decimal places)

Second value of x:

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