Answer:
the ship is at a distance of 60 feet
Step-by-step explanation:
we have to think of the problem as a right triangle, since
we have 2 legs and 1 hypotenuse, we know the measure of the leg that gives us the height and the angle that that leg touches
the leg we want to calculate is the opposite of the angle we have, since it does not touch
well to start we have to know the relationship between angles, legs and the hypotenuse
a: adjacent
o: opposite
h: hypotenuse
sin α = o/h
cos α= a/h
tan α = o/a
we see that it has (angle, adjacent, opposite)
is the tangent
tan α = o/a
tan 22 = o/150
tan 22 * 150 = o
60.6ft = o
round to the nearest foot
60ft
the ship is at a distance of 60 feet
The solution to the problem is as follows:
<span>'(t) = 0 gives:
-24t + 60 = 0
t = 2.5
For this t, the second derivative s"(t) = -24 is negative.
And so, s(t) is maximum for t = 2.5.
Maximum height is:
S = -12(2.5)^2 + 60(2.5) +8 = 233ft
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
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