The displacement would be the final position (37) minus the initial position (50) if using the displacement formula.
From gas equations
PV/T = Constant
Then
P1V1/T1 = P2V2/T2, but V1 = V2
Therefore,
P1/T1 = P2/T2
P2 = (P1T2)/T1
P1 = 40 psi
T1 = 60°F = 288.706 K
T2 = 90°F = 305.372 K
Substituting;
P2 = (40*305.372)/288.706 = 42.31 psi
Then, gauge pressure would read 42.31 psi.
Answer:
in fact, kinetic energy is directly proportional to mass: if you double the mass, then you double the kinetic energy. Second, the faster something is moving, the greater the force it is capable of exerting and the greater energy it possesses. ... Thus a modest increase in speed can cause a large increase in kinetic energy.
Explanation:
Answer:
the linear speed of the car is 28.83 m/s
Explanation:
Given;
radius of the car, r = 0.33 m
angular speed of each tire, ω = 13.9 rev/s = 13.9 x 2π = 87.35 rad/s
The linear speed of the car is calculated as;
V = ωr
V = 87.35 rad/s x 0.33 m
V = 28.83 m/s
Therefore, the linear speed of the car is 28.83 m/s
Answer:
Basically, at these speeds, the car will, at random times, swerve a bit to one side or the other as if hit by some huge wind (even on the calmest of days). It doesn't happen at slower speeds driving mechanically identical cars, managed to accelerate to a formidable 150 mph and stay there for most of the journey, shifting to higher gears and remaining.
Hope this helped you!
Explanation:
