A) Volume = length × width × height
Volume = 6 × 6 × 7
Volume = 252
b) You have to subtract the volume of the water with the stone and the volume of the water without the stone.
Volume = 6 × 6 × 9
= 36 × 9
= 324
324 - 252 = 72.
The volume of the stone is 72 cm^3.
0.2 is the value of coefficient of friction (k)
F=kN
F=horizontal force
n=Normal Force
k=coefficient of friction
k=F/N
k=200/1000
k=0.2
The ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them is known as the friction coefficient. Usually, the Greek letter mu is used to indicate it .N is the normal force, and F is the frictional force, hence F = N/N.
Due to the fact that both F and N are measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds). The coefficient of friction can have a variety of values for both static and dynamic friction. Static friction occurs when an object encounters friction that resists any applied force, keeping the object at rest until the static frictional force is released. In kinetic friction, the frictional force resists the motion of the object.
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Answer:
(a) 62.69 nJ/m^3
(b) 1015.22 μJ/m^3
Explanation:
Electric field, E = 119 V/m
Magnetic field, B = 5.050 x 10^-5 T
(a) Energy density of electric field =
= 6.269 x 10^-8 J/m^3 = 62.69 nJ/m^3
(b) energy density of magnetic field =
= 1.01522 x 10^-3 J/m^3 = 1015.22 μJ/m^3
Answer:
7506 cal
Explanation:
Given: Mass of water = m = 13.9 grams.
Heat energy required to determine the conversion of 13.9 grams of water to steam or vapor is m L,
where L = Latent heat of vaporization of water=540 cal/g.
Q = mL = (13.9)(540) = 7,506 cal.