Start by facing East. Your first displacement is the vector
<em>d</em>₁ = (225 m) <em>i</em>
Turning 90º to the left makes you face North, and walking 350 m in this direction gives the second displacement,
<em>d</em>₂ = (350 m) <em>j</em>
Turning 30º to the right would have you making an angle of 60º North of East, so that walking 125 m gives the third displacement,
<em>d</em>₃ = (125 m) (cos(60º) <em>i</em> + sin(60º) <em>j</em> )
<em>d</em>₃ ≈ (62.5 m) <em>i</em> + (108.25 m) <em>j</em>
The net displacement is
<em>d</em> = <em>d</em>₁ + <em>d</em>₂ + <em>d</em>₃
<em>d</em> ≈ (287.5 m) <em>i</em> + (458.25 m) <em>j</em>
and its magnitude is
|| <em>d</em> || = √[ (287.5 m)² + (458.25 m)² ] ≈ 540.973 m ≈ 541 m
Answer: screen
A mixture of sand, salt and iron can be separated using magnet, filter paper and water. Iron being a magnetic material, can be separated using magnet. The rest of the mixture, salt and sand can be mixed in water. The salt would dissolve in water but sand would not because sand is insoluble in water. This mixture can be filtered using a filter paper. The filter has very minute openings through which sand would not pass through and get separated. Then, salty water can be heated. The water would evaporate leaving behind salt.
In this whole process, screen would not be useful because it would depend on the size of the sand particles and available screen.
Answer:
560nm
Explanation:
You can use the following expression for thin films:
![\lambda=\frac{2nd}{m}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B2nd%7D%7Bm%7D)
where n is the index of refraction, d is the thicknes of the thin film and m is the order of the diffraction pattern. For keratin layers we can use n=1.40. For the longest wavelenth we use m =1.
Hence, we obtain:
![\lambda=\frac{2(1.40)(200nm)}{1}=560nm](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B2%281.40%29%28200nm%29%7D%7B1%7D%3D560nm)
HOPE THIS HELPS!!
The correct answer is letter C, regular reflection.
<span>An image seen in a smooth dinner plate is an example of a
regular reflection. This phenomenon only occurs in smooth and polished surfaces.
During this stage light occurs at a certain angle and is reflected back at the
same angle producing reflections in a way like a mirror does this commonly.</span>