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Artemon [7]
3 years ago
7

Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 13.9 revolutions/s. Find the linear speed v

of the car, assuming that the tires are not slipping against the ground.

Physics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

the linear speed of the car is 28.83 m/s

Explanation:

Given;

radius of the car, r = 0.33 m

angular speed of each tire, ω = 13.9 rev/s = 13.9 x 2π = 87.35 rad/s

The linear speed of the car is calculated as;

V = ωr

V = 87.35 rad/s x 0.33 m

V = 28.83 m/s

Therefore, the linear speed of the car is 28.83 m/s

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In practice, if a voltmeter was connected across any combination of the terminals, the potential difference would be less than w
VladimirAG [237]

Answer:

This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.

Explanation:

A voltmeter is built by a galvanometer and a resistance in series, this set is connected in parallel to the resistance where the voltage is to be measured, therefore the voltage is divided between the voltmeter and the element to be measured, consequently the measured voltage It is less than the calculated one, since for them the resistance of the voltmeter is assumed infinite.

This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.

8 0
3 years ago
Why doesn’t a machine that increases force break the law of conservation of energy?
USPshnik [31]

Answer:

A machine in which work input equals work output. energy can be used to do work, work can be used to transfer energy. The change in the kinetic energy of an object is equal to the net work done on the object.

hope this helps

8 0
3 years ago
Using the periodic table entry below, match the phrases with their corresponding values.
Anika [276]

<u>Answer:</u>

For 1: Atomic number :  79

For 2. Atomic mass : 197

For 3. Number of orbits  : 6

For 4. Number of neutrons : 118

For 5. Number of electrons in n=3 : 18

For 6. Number of valence electrons : 1

<u>Explanation:</u>

  • Atomic number is defined as the number of protons or electrons present in an atom. Here 79 corresponds to the Atomic Number.
  • Atomic mass is defined as the Sum of neutrons and protons present in an atom. Here, 197 corresponds to the Atomic Mass.
  • Atomic Mass = Number of protons + Number of neutrons

Here, Number of protons = 79

So, 197=\text{Number of Neutrons}+79\\\\\text{Number of neutrons}=118

  • Valence electronic configuration of  the atom having atomic number as 79 is : [Xe]5d^{10}6s^1

Number of orbit corresponds the higher value of 'n' which is the principle quantum number. Here, n = 6 so, number of orbits are also 6.

  • In orbit having n = 3, there are 3 sub-shells: s, p and d. The number of electrons that can be occupied in s-subshell = 2

The number of electrons that can be occupied in p-subshell = 6

The number of electrons that can be occupied in d-subshell = 10

Total number of electrons that can be occupied in  orbit having n = 3 are (2 + 6 + 10) = 18 electrons.

  • From the electronic configuration, it is visible that valence electrons in atom having atomic number 79 is 1.
7 0
3 years ago
Read 2 more answers
When particles spread out due to an increase of thermal energy this is called? ​
Lelechka [254]

This sounds like thermal expansion.

5 0
4 years ago
A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect a
pochemuha

Answer:

V=14

Explanation:

PE=KE

mgh=1/2mv^2

2(9.8)10=1/2(2)v^2

(radical) 196= (radical)v

V=14

7 0
3 years ago
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