Answer:
Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s
Explanation:
Given Data:
V is the overall velocity vector, 
and 
are its initial vertical and horizontal components
To find:
Max Height 
achieved
Calculation:
1) Using the 
equation of motion, we know
2) In terms of gravity 
height and the vertical component of Velocity 
.
3) As 
as at maximum height the vertical component of velocity is zero maximum height achieved
putting values
4) 
5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)
There are two particular cases, the first is when Object A is attracted to the neutral wall. This would indicate that the object is not neutral, as there is an attraction.
At the same time we know that Object A is attracted to an object B. And therefore, the load of A must be opposite to that of B. Remember that opposite charges attract each other. If the charge of object B is positive, then the charge of object A will be negative.
Option B is correct: It has a negative charge.
It’s true, because it also depends on things like mass. Higher temperature but less mass< Lower temperature but more mass.
Answer:
f = 1 m
Explanation:
The magnification of the lens is given by the formula:
where,
M = Magnification = 4
q = image distance = 5 m
p = object distance = ?
Therefore,
Now using thin lens formula:
<u>f = 1 m</u>
