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Nuetrik [128]
3 years ago
10

How does speed and mass effect kinetic energy ?

Physics
2 answers:
olganol [36]3 years ago
8 0

Answer: The more mass of an object has, the more Kinetic energy it has.

Explanation:

Kinetic energy is comparable to mass. If you double the mass then you double the kinetic energy. The faster the object is moving the greater the energy possesses. A large increase in speed can have a large increase in kinetic energy.

timurjin [86]3 years ago
4 0

Answer:

in fact, kinetic energy is directly proportional to mass: if you double the mass, then you double the kinetic energy. Second, the faster something is moving, the greater the force it is capable of exerting and the greater energy it possesses. ... Thus a modest increase in speed can cause a large increase in kinetic energy.

Explanation:

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Consider the following hypotheses: 12:V ) >(x)) Use rules of inference to prove that the following conclusion follows from th
Igoryamba

Answer: See attachment below

Explanation:

8 0
3 years ago
What is the average density of a neutron star that has the same mass as the sun but a radius of only 20.0 km?
IrinaK [193]

Answer: 5.935(10)^{13}g/cm^{3}}

Explanation:

Density is a characteristic property bodies and materials, and is defined as the relationship between the mass m and the volume V, as shown below:

D=\frac{m}{V}  (1)

In the case of the neutron star, we know it has the same mass as the Sun:

m=1.989(10)^{30}kg

And its radius is r=20km

On the other hand, if we assume this neutron star has a spherical shape, its volume  can be calculated by the following formula:

V=V_{sphere}=\frac{4}{3}\pir^{3}   (2)

V=\frac{4}{3}\pi(20km)^{3}   (3)

V=33510.321km^{3}   (4)

Substituting (4) in (1):

D=\frac{1.989(10)^{30}kg}{33510.321km^{3}}  (5)

Finally:

D=5.935(10)^{25}kg/km^{3}}=5.935(10)^{13}g/cm^{3}}  

4 0
3 years ago
Which one of the risk factors that influence you learn how may be most difficult to control as a young teen
nalin [4]
I hope my answer helped u under stand better
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3 years ago
A train traveling at 27.5 accelerates to 42.4 m s over 75.0 s What is the displacement of the train in this time period A train
jarptica [38.1K]

Answer:

The displacement of the train in this time period is 2,616.86 m.

Explanation:

A Uniformly Varied Rectilinear Motion is Rectilinear because the mobile moves in a straight line, Uniformly because of there is a magnitude that remains constant (in this case the acceleration) and Varied because the speed varies, the final speed being different from the initial one.

In other words, a motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time (the speed is constant and the acceleration is variable).

An independent equation of useful time in this type of movement is:

vf^{2} =vi^{2} +2*a*d <em>Expression A</em>

where:

  • vf = final velocity
  • vi = initial velocity
  • a = acceleration
  • d = distance

The equation of velocity as a function of time in this type of movement is:

vf=vi + a*t

So the velocity can be calculated as: a=\frac{vf-vi}{t}

In this case:

  • vf=42.4 m/s
  • vi=27.5 m/s
  • t=75 s

Replacing in the definition of acceleration:  a=\frac{42.4 m/s-27.5 m/s}{75 s}

a=0.199 m/s²

Now, replacing in expression A:

(42.4 m/s)^{2} =(27.5 m/s)^{2} +2*(0.199 m/s^{2}) *d

Solving:

d= \frac{(42.4 m/s)^{2} - (27.5 m/s)^{2} }{2*(0.199 m/s^{2}) }

d= 2,616.86 m

<u><em>The displacement of the train in this time period is 2,616.86 m.</em></u>

4 0
3 years ago
What is the oxidation number of the noble gases such as xenon and argon?
OLga [1]
Oxidation number for Xenon is XeOF2 and Argon is 0.
6 0
3 years ago
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