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3 years ago

Definition for axis of symmetry

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

3 0

Answer:

An axis of symmetry is a line about which a figure is symmetrical. If a figure can be folded such that the two parts exactly match, the fold line is an axis of symmetry. A figure can have one line of symmetry, many lines of symmetry, or no lines of symmetry.

Step-by-step explanation:

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In kite WXYZ, mZWY = 41° and mXYW = 11°<br><br><br> What is mWZY?

olchik [2.2K]

Answer:

128°

Step-by-step explanation:

In kite WXYZ, WY and XZ are longer and smaller diagonals respectively.

Longer diagonal bisects the opposite angles.

$\therefore m\angle ZYW =m\angle XYW$

$\because m\angle XYW = 11\degree... (given)$

$\therefore m\angle ZYW =11\degree$

$In\: \triangle WYZ$

$m\angle ZYW + m\angle ZWY + m\angle WZY=180\degree$

$11\degree + 41\degree+ m\angle WZY=180\degree$

$52\degree+ m\angle WZY=180\degree$

$m\angle WZY=180\degree - 52\degree$

$\purple{\bold {m\angle WZY=128\degree}}$

8 0

3 years ago

a crate of mass 50kg is dragged by an engine along a horizontal floor through distance of 6m in 3s. calculate the power of the e

ss7ja [257]

Answer:

9000watts

Step-by-step explanation:

m=50kg

g=10

h=6

t=3

formula=work done×time

work done=m×g×h

Answer=m×g×h×t

50*10*6*3=9000watts

4 0

2 years ago

.. Which of the following are the coordinates of the vertices of the following square with sides of length a?

atroni [7]

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Step-by-step explanation:

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

To find the sides of a square, let us use the distance formula,

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,a), T(a,a), W(a,0)$ has sides of length a.

Option B: $O(0,0), S(0,a), T(2a,2a), W(a,0)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

This is not a square because the lengths are not equal.

Option C: $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$ has sides of length 2a.

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

Thus, the square with vertices $O(0,0), S(a,0), T(a,a), W(0,a)$ has sides of length a.

Thus, the correct answers are option a and option d.

8 0

3 years ago

A department store sells yellow and purple shirts. Each yellow shirt is the same price. Each purple shirt is the same price. How

Aleksandr [31]

Answer:

The Cost of yellow shirts is $15 and the cost of purple shirt is $ 60

Step-by-step explanation:

Let cost of one yellow shirt be x

and the cost of one purple shirt be y

On Monday

5x + 7y = 165--------------------(1)

On Tuesday

4x + 11y = 213----------------------(2)

To solve (1) and (2)

multiplying eq(1) with 4

20x + 28y = 660--------------------(3)

multiplying eq(2) with 5

20x + 55y = 1056-------------------(4)

Subtracting (3) from (4)

20x + 55y = 1056

20x + 28y = 660

(-)

-----------------------------------

0x +27y = 405

-----------------------------------

$y = \frac{405}{27}$

y = 15

Substituting y value in eq(1)

5x + 7(15) = 165

5x + 105 =405

5x =405 -105

5x =300

x = \frac{300}{5}

x =60

7 0

3 years ago

Read 2 more answers

Solve for m. t=ms/m+n

sukhopar [10]

T(m+n)=ms
Tm+tn=ms
2tn/s=2m

8 0

3 years ago