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nordsb [41]
3 years ago
14

Is the arctic ocean larger than the indian ocean?

Physics
1 answer:
Alik [6]3 years ago
5 0
The Arctic Ocean is the smallest ocean. It is more than five times smaller than Indian and Atlantic Oceans.
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What happens in the crushing can experiment?
Dafna1 [17]

Explanation:

When hot water is poured on the can in a bucket of cold water, the can crushes off means it gets unshaped

7 0
3 years ago
Read the paragraph below and answer the question that follows:
elena-s [515]

B. Helium because it is constantly being made in the sun

Explanation:

From the given paragraph, we can conclude that helium is the most common element in a star such as the sun because it is constantly being made.

In the nuclear fusion process that results in the production of helium, hydrogen nuclei are the reactants and helium is the product.

  • since the reactants are constantly being used in the core of the sun, this suggests that the products must be more.
  • The reaction requires a high temperature and pressure to initiate.
  • It is a series of chain reaction that uses a fuel of hydrogen to produce helium.

learn more:

Transmutation brainly.com/question/3433940

#learnwithBrainly

8 0
3 years ago
A 5.75 × 107 kg battle ship originally at rest fires a 1100-kg artillery shell horizontally with a velocity of 550 m/s. show ans
prohojiy [21]

Answer:

-0.01052 m/s

Explanation:

M = mass of ship = 5.75\times 10^7\ kg

m = mass of shell = 1100 kg

v = velocity of shell = 550 m/s

u = recoil velocity of ship

As linear momentum is conserved

(M - m)u=-mv\\\Rightarrow u=-\frac{mv}{M - m}\\\Rightarrow u=-\frac{1100\times 550}{5.75\times 10^7+1100}\\\Rightarrow u=-0.01052\ m/s

The recoil velocity of the ship taking the firing direction to be the positive direction is -0.01052 m/s

6 0
3 years ago
three girls were pushing the same car with a net force of 450 N [N48°E]. Two of the girls were pushing with forces of 310 N [N25
ElenaW [278]

The net force is the vector

∑ F = (450 N) (cos(42°) i + sin(42°) j)

and two of the forces provided by the girls are

F₁ = (310 N) (cos(115°) i + sin(115°) j)

F₂ = (250 N) (cos(285°) i + sin(285°) j)

Then the force provided by the third girl is the vector

F₃ = ∑ F - F₁ - F₂

F₃ = ((450 N) cos(42°) - (310 N) cos(115°) - (250 N) cos(285°)) i

… … … + ((450 N) sin(42°) - (310 N) sin(115°) - (250 N) sin(285°)) j

F₃ ≈ (400.722 N) i + (261.635 N) j

So, the third girl provided a force of magnitude

||F₃|| = √((400.722 N)² + (261.635 N)²) ≈ 478.572 N ≈ 480 N

pointing in a direction

arctan((261.635 N)/(400.722 N)) ≈ 33.1409° ≈ 33°

relative to East which refers to 0°; that is, 33° N of E or E33°N. Since the other forces are given relative to North or South, we can write this direction as N57°E.

So, the third girl pushed with force 480 N [N57°E].

5 0
3 years ago
A solid sphere of mass 8.6 kg, made of metal whose density is 3,400 kg/, hangs by a cord. When the sphere is immersed in a liqui
creativ13 [48]

Answer:

A.1900 kg/m^3

Explanation:

We are given that

m=8.6 kg

Density,\rho_s=3400 kg/m^3

Tension,T=38 N

We have to find the density of liquid.

T=mg-\rho_l Vg

g=9.8 m/s^2

Volume,V=\frac{m}{\rho_s}

38=8.6\times 9.8-\rho_l\times \frac{8.6}{3400}\times 9.8

\rho_l\times \frac{8.6}{3400}\times 9.8=8.6\times 9.8-38

\rho_l=\frac{(8.6\times 9.8-38)\times 3400}{8.6\times 9.8}

\rho_l=1867kg/m^3\approx 1900 kg/m^3

Option A is true.

4 0
3 years ago
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