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3 years ago

Is the arctic ocean larger than the indian ocean?

Physics

1 answer:

Alik [6]3 years ago

5 0

The Arctic Ocean is the smallest ocean. It is more than five times smaller than Indian and Atlantic Oceans.

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If two variables have a non-related relationship and one of the variables is changed, how will the other variable change?

PolarNik [594]

If one of the variables is changed, that tells nothing about what happens to the other one, or IF anything happens, or when, or how long it lasts. Because they are UN-RELATED. You just said so yourself.

None of the choices says this.

6 0

3 years ago

Newton's first law equations like velocity and stuff like that

Klio2033 [76]

Answer:

Newton's first law: An object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force. ... An object sliding across a table or floor slows down due to the net force of friction acting on the object.

Explanation:

please give me a heart

4 0

3 years ago

Melanye and Kaitlynn were traveling on a train for 6 hours. Over that time the train was at an average velocity of 70km/hr west.

slega [8]

The way he got the wrong guy to get back into the car he was just saying that I didn’t need it for me so he said no I’m gonna do tell you I have a little girl that was going on a little bit of a girl and I

8 0

2 years ago

The force that pulls falling objects toward Earth is called *

larisa [96]

Answer:

Gravity

Explanation:

That's easy because gravity is the only thing that can pull us down that hard at that fast without anything helping it.

5 0

2 years ago

The membrane that surrounds a certain type of living cell has a surface area of 7.1 x 10-9 m2 and a thickness of 1.5 x 10-8 m. A

hoa [83]

Answer:

Q = +1.4 pC

Explanation:

The capacitance of any capacitor, by definition, is as follows:
$C = \frac{Q}{V} (1)$
Applying Gauss'Law and the definition of electric potential, it can be showed that the capacitance of a parallel-plate capacitor can be expressed as follows:
$C = \frac{\epsilon_{r}*\epsilon_{0} * A}{d} (2)$
Where εr is the dielectric constant of the material that fills the space between the plates, A is the area of one of the plates, and d, is the separation between them.
Replacing by the givens in (2) we can find the value of the capacitance C, as follows:

$C = \frac{\ 4.4*8.85e-12C2/N*m2*7.1e-9m2}{1.5e-8m} = 18.4e-12 F = 18.4 pF$

Replacing the values of C and V in (1), we can solve for Q, as follows:

$Q = C*V = 18.4e-12 F* 75.9e-3 V = 1.4e-12 C = +1.4 pC$

As the outer surface is at a higher potential that the inside surface, the charge on it must be positive, and is equal to +1.4 pC.

7 0

3 years ago