Answer:
maybe c. because if you do 70
Explanation:
-50 you get 20 than you add that to the 25 and you get 45 and the nearest closest number is 47
<span>northwest Australia between Exmouth and Broome in Western Australia and in northeast Queensland between Port Douglas and Maryborough</span>
Answer: 2.46m
Explanation:
Given that:
force = 334 N
Work on an object = 823 J
Displacement = ?
Recall that work is done when force is applied on an object over a distance (when the object is displaced in a particular direction)
i.e Work = Force x Displacement
823J = 334 N x displacement
Displacement = 823J / 334N
Displacement = 2.46m
Thus, a displacement of 2.46 metres was made in the work.
in that work
Answer:
a) Δx₂ = 31*Δt
b) Δx₁ = 977.5 / a
c) a = 23 / Δt
e) Δx₁ = 42.5*Δt
g) Δt = 0.0565 h
i) a = 0.05 m/s²
Explanation:
Given
v₁ = 54 Mi/h
v₂ = 31 Mi/h
a) We apply the formula
Δx₂ = v₂*Δt
⇒ Δx₂ = 31*Δt (Assuming constant speed)
b) We use the formula
v₂² = v₁² - 2*a*Δx₁ ⇒ Δx₁ = (v₁² - v₂²) / (2*a)
⇒ Δx₁ = (54² - 31²) / (2*a)
⇒ Δx₁ = 977.5 / a
c) We use the equation
v₂ = v₁ - a*Δt ⇒ a = (v₁ - v₂) / Δt
⇒ a = (54 - 31) / Δt
⇒ a = 23 / Δt
e) We apply the formula
Δx₁ = v₁*Δt - 0.5*a*Δt²
Δx₁ = 54*Δt - 0.5*(23 / Δt)*Δt²
⇒ Δx₁ = 42.5*Δt
g) If Δx₁ = 2.4 Mi ⇒ 2.4 = 42.5*Δt ⇒ Δt = 0.0565 h
i) If a = 23 / Δt ⇒ a = 23 Mi / 0.0565 h = 407.29 Mi/h²
⇒ a = 0.05 m/s²
