Answer:
The answer is below
Explanation:
a) The vertical displacement = Δy = 21.5 m - 1.5 m = 20 m
The horizontal displacement = Δx = 69 m wide
Using the formula:

Also:

b)The car is moving at a constant speed in the horizontal direction, hence the initial velocity = final velocity

True as the independent variable is over the dependent variable and controls it as the dependent relies on the independent.
Explanation:
a) P = IV
2000 W = I (230 V)
I = 8.7 A
b) The fuse must be rated for a higher current than the kettle, so use the 13A fuse.
c) Double insulation means there are two layers of insulation, insuring that the wires cannot touch the outer casing of the kettle and protecting the user from electrical shock.
d) V = IR
230 V = (8.7 A) R
R = 26.5 Ω
Given that the arc length is:
s = ∫ √[1² + (dy/dx)²] dx
<span>So arc length between the two points is then: </span>
<span>s = 2*20sinh(x/20)
= 40sinh(x/20) </span>
<span>The straight distance between the two points is : d = 2x </span>
<span>So, x = d/2.
= 40/2
= 20 m </span>
<span>Plug this into the arc length equation to get:
s = 40sinh[20/20)]
=40* ½ (e - 1/e) </span>
<span> = 47 m</span>
Answer:
d. 332 V
Explanation:
Given;
number of turns in the wire, N = 40 turns
area of the coil, A = 0.06 m²
magnitude of the magnetic field, B = 0.4 T
frequency of the wave, f = 55 Hz
The maximum emf induced in the coil is given by;
E = NBAω
Where;
ω is angular velocity = 2πf
E = NBA(2πf)
E = 40 x 0.4 x 0.06 x (2 x π x 55)
E = 332 V
Therefore, the maximum induced emf in the coil is 332 V.
The correct option is "D"
d. 332 V