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anygoal [31]
3 years ago
8

At the beginning of a unit on forces, Ms. Alton is leading a class discussion asking her students

Physics
1 answer:
VMariaS [17]3 years ago
6 0

Answer:

(iv), (v), (vi) would be incorrect.

Explanation:

(iv) Force isn't transferred from one colliding object to another, but momentum can be.

(v) An object doesn't stop immediately a force stops acting on it. Think of a thrown ball.

(vi) For an object not to move, it means that the net force on the object is zero, and not necessarily that there are no forces acting on the object. For example, an object could be pushed on one side, and be pushed on the other side with an equal force in the opposite direction. The forces would cancel each other and the net force would be zero.

The rest should be correct.

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A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten
babymother [125]

Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

8 0
3 years ago
If a 25 kg object is moving at a velocity of 10 m/s, the object has<br> energy. Calculate it.
Paul [167]

Answer: Your answer is 1250J

Explanation:

K E = 1/2 m v 2

The mass is  

m = 25 k g

The velocity is  v = 10 m s − 1

So,

K E = 1 /2 x25 x 10 2^2= 1250 J

pls mark brainiest answer  

4 0
2 years ago
Which is heavier , a kilogram of lead or a kilogram of a polystyrene beads ?​
Mars2501 [29]

Answer:

They weight the same, they're both 1 kilogram

3 0
3 years ago
Read 2 more answers
a car accelerates from rest to a velocity of 5meters/second in 4 seconds. what is its average acceleration over this period of t
Pani-rosa [81]

Answer:

1.25 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (5 m/s − 0 m/s) / 4 s

a = 1.25 m/s²

6 0
3 years ago
What happens to light when it strikes the inside surface of a smooth, curved mirror? It bounces in random directions. It bounces
kotykmax [81]
This is a concave mirror you're talking about, so all of the points are going to converge to a single focal point. Therefore the answer would be that it bounces back toward a single spot
5 0
3 years ago
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