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leva [86]
4 years ago
8

A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) I

f the goalie catches the puck with his glove in a time of 2.33 x 10-3 s, what is the magnitude of the average force exerted on the goalie by the puck?
Physics
1 answer:
viktelen [127]4 years ago
4 0

Answer:

2991.42 N

Explanation:

For this problem, we'll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.

initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s

final momentum; p2 = 0, because final velocity is 0 m/s

Thus,

impulse = p1 - p2= 6.97 - 0 = 6.97 kg.m/s

Finally, impulse= Force x time,

Thus, Force = Impulse/time

Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N

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List down atleast five activities where friction gave you an undesirable experience
Step2247 [10]

Answer:

Rug burn, Indian burn done to you by a friend, friction from the road causes your car to accelerate at a slower rate, The cylinder heads in an engine, When trying to move a heavy object across a rough surface

Explanation:

7 0
3 years ago
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From 0 seconds to 4 seconds is the acceleration positive or negative?
Alenkinab [10]

Answer:

From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)

From 6-10 seconds the acceleration is negative. (The graph is going downwards.)

7 0
3 years ago
How does this picture apply to Newtons 3rd law.Please make it well developed!!!Thanks!
Orlov [11]

<u>Explanation for the given picture:</u>

Initially, three principles of movement proposed by Sir Isaac Newton in 1686 "Principia Mathematica Philosophiae Naturalis". The third law says that every action (force) in nature has an equal but has opposite reaction.

In other words, when object A produces force on object B, then this object B also exerts the same but opposite forces on object A. Remember that forces get exerted on various objects. For example, if we put a wooden block in the floor, this block will create a force that should be equal to its mass, W = mg, which will work down.  

The photo above clearly shows a person jumping off a tree on a wooden board, and therefore bouncing on the board because of the force exerted by the wooden board. Newton's third law is important if a person uses his power as weight (W = mg), and this in turn turns the person upside down! hence

Newtons 3rd law applies in above picture.

5 0
3 years ago
Find the 24th term of the arithmetic sequence 11, 14, 17, … . Express the 24 terms of the series of this sequence using sigma no
Anna71 [15]

Answer:

The 24th term is 80 and the sum of 24 terms is 1092.

Explanation:

Given that,

The arithmetic series is

11,14,17,........24

First term a = 11

Difference d = 14-11=3

We need to calculate the 24th term of the arithmetic sequence

Using formula of number of terms

t_{n}=a+(n-1)d

Put the value into the formula

t_{24}=11+(24-1)\times3

t_{24}=80

t_{24}=u_{24}=80

We need to calculate the sum of the first 24 terms of the series

Using formula of sum,

S_{n}=\dfrac{n}{2}(a+u_{24})

Put the value into the formula

S_{n}=\dfrac{24}{2}\times(11+80)

S_{n}=1092

Hence, The 24th term is 80 and the sum of 24 terms is 1092.

5 0
4 years ago
You throw a ball straight up with an initial velocity of 15.0 m/s. It passes a tree branch on the way up at a height of 7.00 m.
Gwar [14]

Answer:

0.95 seconds

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration = 9.81 m/s² (downward positive, upward negative)

Time taken by the ball to reach the maximum height

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-15}{-9.81}\\\Rightarrow t=1.52\ s

Maximum height

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-15^2}{2\times -9.81}\\\Rightarrow s=11.47\ m

Distance between maximum height of the ball and the branch is 11.47-7 = 4.46 m

So, the distance that will be covered on the way down is 4.46 m

Now

u = 0

s = 4.46

s=ut+\frac{1}{2}at^2\\\Rightarrow 4.46=0\times t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4.46\times 2}{9.81}}\\\Rightarrow t=0.95\ s

Time taken by the ball from the maximum height to the tree branch is 0.95 seconds.

Total time taken from the moment the ball is thrown to reach the tree branch is 1.52+0.95 = 2.47 seconds

7 0
3 years ago
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