Answer:
I think it might be A
Explanation:
the reason I think this answer is because the intensity is 50%.
Answer:
ω, the angular frequency of the source equals 377 rad/s
Explanation:
From the question, V(t) = V cosωt.
Now, ω = the angular frequency of the sinusoidal wave is given by
ω = 2πf where f = the frequency of the source = 60 Hz
So, the angular frequency of the source ,ω = 2π × the frequency of the source.
So, ω = 2πf
ω = 2π × 60 Hz
ω = 120π rad/s
ω = 376.99 rad/s
ω ≅ 377 rad/s
So, ω, the angular frequency of the source equals 377 rad/s
Forecasters must consider a large number of variables that affect the path of the storm.
This makes it difficult to create computer-based models because all of these variables are hard to incorporate.
Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:
Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:
Using the arcsin properties, we get:

Obs: Approximate results, and the drawing is attached
If you notice any mistake in my english, let me know, because i am not native.