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podryga [215]
4 years ago
15

Find the 24th term of the arithmetic sequence 11, 14, 17, … . Express the 24 terms of the series of this sequence using sigma no

tation. Find the sum of the first 24 terms of the series.
Physics
1 answer:
Anna71 [15]4 years ago
5 0

Answer:

The 24th term is 80 and the sum of 24 terms is 1092.

Explanation:

Given that,

The arithmetic series is

11,14,17,........24

First term a = 11

Difference d = 14-11=3

We need to calculate the 24th term of the arithmetic sequence

Using formula of number of terms

t_{n}=a+(n-1)d

Put the value into the formula

t_{24}=11+(24-1)\times3

t_{24}=80

t_{24}=u_{24}=80

We need to calculate the sum of the first 24 terms of the series

Using formula of sum,

S_{n}=\dfrac{n}{2}(a+u_{24})

Put the value into the formula

S_{n}=\dfrac{24}{2}\times(11+80)

S_{n}=1092

Hence, The 24th term is 80 and the sum of 24 terms is 1092.

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Kepler's research was based on the data and observations of which person?
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The answer is A. Tycho Brahe
6 0
3 years ago
To pull a 50 kg crate across a horizontal frictionless floor, a worker applies a force of 210 N, directed 20° above the horizont
tangare [24]

Answer:

Explanation:

Given that,

A crate of mass M = 50kg

The crate is pulled along an horizontal floor by a string at an angle

Force pulling the crate

F = 210N

Angle θ = 20° to the horizontal

Distance moved by crate d=3m

A. Work done by force

W = FdCosθ

W = 210 × 3 × Cos20

W = 592J

B. Work done by Gravitational force?

Work is define as the dot product of force and displacement in the direction of the force.

Since the gravitational force does not cause the crate to move any distance downward

Then,

W(gravity) = mg×d

distance d=0

W(gravity) = 0 J

C. Work done by normal?

Since, the normal force did not cause the crate to move upward by any distance

Then,

W(normal) = 0J

D. The total workdone?

The only workdone on the crate is by the person

Then, the total workdone is the workdone by the person

W = 592 J

4 0
3 years ago
Please help!!! 80 feet/sec to miles / hour
SCORPION-xisa [38]
I’m not sure what your asking explain
3 0
3 years ago
Read 2 more answers
A 25-g string is stretched with a tension of 43 N between two fixed points 12 m apart. What is the frequency of the second harmo
Svetllana [295]

Answer:

The frequency of the second harmonic (2f_o) is 11.97 Hz.

Explanation:

Given;

mass of the string, m = 25 g = 0.025kg

tension on the string, T = 43 N

length of the string, L = 12 m

The speed of wave on the string is given as;

v = \sqrt{\frac{T}{\mu} }

where;

μ is mass per unit length = 0.025 / 12 = 0.002083 kg/m

v = \sqrt{\frac{43}{0.002083} }\\\\v  = 143.678 \ m/s

The wavelength of the first harmonic wave is given as;

L = \frac{1}{2} \lambda _o\\\\\lambda _o = 2L \\\\\lambda _o = 2 \ \times \ 12\\\\\lambda _o = 24 \ m

The frequency of the first harmonic is given as;

f_o = \frac{v}{\lambda _o} = \frac{v}{2L} = \frac{143.678}{24} = 5.99 \ Hz\\\\

The wavelength of the second harmonic wave is given as;

L = \lambda_1 \\\\\lambda_1 = 12 \ m

The frequency of the second harmonic is given as;

f_1 = \frac{v}{\lambda _1} = \frac{143.678}{12} = 11.97 \ Hz = 2(\frac{v}{\lambda _0}) = 2f_o

Therefore, the frequency of the second harmonic (2f_o) is 11.97 Hz.

8 0
3 years ago
1) La corriente de un inductor de 90.0 mH cambia con el transcurso del tiempo de la forma I = 1.00 t 2 – 6.00 t (en unidades del
Gala2k [10]

Answer:

a)   E_{L} = -360 V , b)      t = 3 s

Explanation:

The electromotive force in an inductor is

           E_{L} = - L dI/ dt

in the exercise they give us the relation of i (t)

            i (t) = 1.00 t² -6.00t

we carry out the derivative and substitute

          E_{L} = - L (2.00 2t - 6.00 1)

a) the electromotive force at t = 1.00 s

          E_{L} = - 90.0 (4.00 1 - 6.00)

         E_{L} = -360 V

b) for t = 4 s

         E_{L}= - 90 (2 4 2 - 6 4)

         E_{L} = - 720 V

c) for the induced electromotive force to zero, the amount between paracentesis must be zero

           (2.00 t2 - 6.00t) = 0

            t (2.0 t-6.00) = 0

the solutions of this equation are

            t = 0

            2 t -6 = 0

            t = 3 s

to have a different solution the trivial (all zero) we must total t = 3 s

4 0
4 years ago
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