The answer is A. Tycho Brahe
Answer:
Explanation:
Given that,
A crate of mass M = 50kg
The crate is pulled along an horizontal floor by a string at an angle
Force pulling the crate
F = 210N
Angle θ = 20° to the horizontal
Distance moved by crate d=3m
A. Work done by force
W = FdCosθ
W = 210 × 3 × Cos20
W = 592J
B. Work done by Gravitational force?
Work is define as the dot product of force and displacement in the direction of the force.
Since the gravitational force does not cause the crate to move any distance downward
Then,
W(gravity) = mg×d
distance d=0
W(gravity) = 0 J
C. Work done by normal?
Since, the normal force did not cause the crate to move upward by any distance
Then,
W(normal) = 0J
D. The total workdone?
The only workdone on the crate is by the person
Then, the total workdone is the workdone by the person
W = 592 J
I’m not sure what your asking explain
Answer:
The frequency of the second harmonic (
) is 11.97 Hz.
Explanation:
Given;
mass of the string, m = 25 g = 0.025kg
tension on the string, T = 43 N
length of the string, L = 12 m
The speed of wave on the string is given as;

where;
μ is mass per unit length = 0.025 / 12 = 0.002083 kg/m

The wavelength of the first harmonic wave is given as;

The frequency of the first harmonic is given as;

The wavelength of the second harmonic wave is given as;

The frequency of the second harmonic is given as;

Therefore, the frequency of the second harmonic (
) is 11.97 Hz.
Answer:
a) E_{L} = -360 V
, b) t = 3 s
Explanation:
The electromotive force in an inductor is
= - L dI/ dt
in the exercise they give us the relation of i (t)
i (t) = 1.00 t² -6.00t
we carry out the derivative and substitute
E_{L} = - L (2.00 2t - 6.00 1)
a) the electromotive force at t = 1.00 s
E_{L} = - 90.0 (4.00 1 - 6.00)
E_{L} = -360 V
b) for t = 4 s
E_{L}= - 90 (2 4 2 - 6 4)
E_{L} = - 720 V
c) for the induced electromotive force to zero, the amount between paracentesis must be zero
(2.00 t2 - 6.00t) = 0
t (2.0 t-6.00) = 0
the solutions of this equation are
t = 0
2 t -6 = 0
t = 3 s
to have a different solution the trivial (all zero) we must total t = 3 s