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3 years ago

List down atleast five activities where friction gave you an undesirable experience

2 answers:

8 0

Carpet burn - where you fall super fast on carpet, and the friction gives you a burn

Driving a car - friction may slow it down

Pulling/pushing an object on the floor - friction will make it harder to pull/push

Playing air hockey on the floor - friction will stop the puck

Pushing a ball down a road - friction will make the ball stop at a faster rate

Step2247 [10]3 years ago

7 0

Answer:

Rug burn, Indian burn done to you by a friend, friction from the road causes your car to accelerate at a slower rate, The cylinder heads in an engine, When trying to move a heavy object across a rough surface

Explanation:

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Existing rocks can become sedimentary rocks when they are subjected to which conditions?

Svetllana [295]

The correct answer is C. Since that really was a tricky question I made sure it was correct by checking on Google. Hope I helped! - Amber

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3 years ago

Traveling in a circle requires a net force

sergij07 [2.7K]

I don’t think I understand the question but true?

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3 years ago

Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia

Oksanka [162]

Answer:

B meet A 0.01 km east of flagpole

Explanation:

given data

distance A = 5.7 km west

velocity V1 = 8.9 km/h

distance B = 4.5 km east

velocity V2 = 7 km/h

to find out

How far runners from the flagpole, when paths cross

solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

and we consider here B will run distance x km for meet

so time will be for B is

time B = distance / velocity

time B = x / 7 ...................1

and

for A distance for meet = ( 10.2 - x ) km

so time A = distance / velocity

time A = ( 10.2 - x ) / 8.9 .............2

now equating equation 1 and 2

time A = time B

x / 7 = ( 10.2 - x ) / 8.9

x = 4.490

so distance of B run for meet is 4.490 km

so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km

so B meet A 0.01 km east of flagpole

4 0

3 years ago

When a wave passes from one medium to another, its _________ remains constant.

Mashcka [7]

The frequency will not change

3 0

3 years ago

Suppose that two point charges, each with a charge of +1.00 C, are separated by a distance of 1.0 m. If the distance between the

Aleksandr-060686 [28]

Given:

The magnitude of each charge is q1 = q2 = 1 C

The distance between them is r = 1 m

To find the force when distance is doubled.

Explanation:

The new distance is

$\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}$

The force can be calculated by the formula

$F=k\frac{q1q2}{(r^{\prime})^2}$

Here, k is the constant whose value is

$k=9\times10^9\text{ N m}^2\text{ /C}^2$

On substituting the values, the force will be

$\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}$

7 0

1 year ago