Hi!
<h3>Put in the values. </h3>
[z+8(5-2)]^2/4
<h3>Now use PEMDAS to solve. </h3>
- Parentheses - Subtraction
[z+8*3]^2/4
- Parentheses - Multiplication
[z+24]^2/4
z+576/4
<u>z+144</u>
<h2>When you evaluate [a+8 (b-2)]^2÷4, you get z + 144</h2>
Hope this helps! :)
-Peredhel
Answer:
8.95feet
Step-by-step explanation:
The set up is a right angled triangle where;
The camera's horizontal distance from the focus point = 26feet = Adjacent;
The height of the camera above the floor = Opposite = x
Angle of elevation = 19°
According to TOA in trig identity;
Tan theta = opp/adj
Tan 19 = x/26
x = 26tan 19
x = 26(0.3443)
X = 8.95feet
Hence the camera is placed at a height of 8.95feet above the floor