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Goryan [66]
3 years ago
12

Thematics

Mathematics
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

x  =  4 your welcome.

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Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
The table below shows the relationship between the number of calories burned and the minutes of exercise.
sergejj [24]

Answer:

Option B

Step-by-step explanation:

Since, number of calories 'C' burned is proportional to the number of minutes (m) given to the exercise,

C ∝ m

C = km

Where k is the proportionality constant.

From the table attached,

For C = 250 calories and m = 30 minutes,

250 = 30k

k = \frac{250}{30}

  = \frac{25}{3}

Therefore, equation representing this situation will be,

C = \frac{25}{3}m

Option B will be the correct option.

5 0
3 years ago
Brett is 75 feet from the base of a building. he measures the angle of elevation to the top of the building and records it as 80
SashulF [63]
This is the concept of trigonometry, we are required to calculate the number of floors the building has given the information above;
# floors=[height of the building]/[height of each floor]
height of each floor=17 ft
let the height of the building be,h.
h is given by;
tan theta=opposite/adjacent
theta=80
opposite=h
adjacent=75 ft
thus
tan 80=h/75
h=75 tan 80
h=425.35 ft
thus the number of floors will be:
425.35/17
=25.020≈25 floors


8 0
3 years ago
Rewrite terms that are subtracted as addition of the opposite. g2 + (–4g4) + 5g + 9 + (–3g3) + 3g2 + (–6) Group like terms. Comb
Vilka [71]

Answer:

-4g^4 -3g^3 + 4g^2 +5g +3

Step-by-step explanation:

g^2 + -4g^4 +5g +9 -3g^3 + 3g^2 -6

-4g^4 -3g^3 + 4g^2 +5g +3

3 0
3 years ago
Slope 2 passing through 10,8
nlexa [21]
Use y=Mx+b    with x=10 and y=8
4 0
3 years ago
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