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nalin [4]
4 years ago
14

Solve for c of the right triangle

Mathematics
2 answers:
Ede4ka [16]4 years ago
5 0
In order to solve this triangle we must use cosine law:
c^{2} = a^{2} + b^{2} - 2ab*cosC

Now let's plug in the values we are given:
c^{2} = 5^{2} + 8^{2} - 2(5)(8) * cos 67
c^{2} = 25 + 64 - 80*cos67
c =  \sqrt{80-cos67}

DochEvi [55]4 years ago
5 0
From the Law of Cosines, we know
<span>b=8 a=5 angle C=67
side c² = a² + b² -2ab • cos(C)
</span><span>side c² = 5^2 +8^2 -2*5*8 * cos (67)
</span><span>side c² = 25 + 64 -(80*.39073)
</span>side c² = 89 - <span> <span> <span> 31.2584 </span> </span> </span>
<span><span><span>side c² = 57.7416 </span> </span> </span>
side c = <span> <span> <span> 7.5987893773 </span> </span> </span>



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