The Power of a Power Rule. In this case, you basically multiply the two exponents together, and simplify (x^4)^9 to equal x^36
The closest option to the actual answer is a.
1 5/18 is the actual answer.
If you make both the denominators the same, then you can actually add the fractions together.
To make both of the denominators the same, you need to multiply 5/6 by 9 and 4/9 by 6, which would result in 45/54 + 24/54= 69/54 = 23/18. If we convert it to a mixed fraction, it would result into 1 5/18.
<span>(x, y)→(x − 8, y − 7) is the correct translation. Take point D for example. The coordinate of D is (2, 5). The coordinate of D' (after translation) is (-6, -2). Since 2-8=-6, 5-7=-2, only the first choice is correct. You can also try other points and see why only this is the right translation.</span>
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
Answer:
This makes no sence at all likee
Step-by-step explanation:
