Am i correct? Your solution would be <span><span>y=<span>yc</span>+<span>yp</span></span></span>
Answer:
a) C. The random variable is discrete. The possible values are xequals0, 1, 2,....
b) B. The random variable is continuous. The possible values are x greater than or equals 0.
Step-by-step explanation:
Discrete variables are countable in a finite amount of time. Continuous variables can be infinitely many. They rather assume values in a range.
<u><em>(a) Is the number of hits to a Web site in a day discrete or continuous? </em></u>
C. The random variable is discrete. The possible values are x equals 0, 1, 2,....
<u><em>(b) Is the weight of a Upper T dash bone steak discrete or continuous?</em></u>
B. The random variable is continuous. The possible values are x greater than or equals 0.
What I would do with is just multiply the 125 by half an hour yeah or just multiply the ones we five by in half an hour and get your final answer I multiply the 1.25 by 1.2 and I got 1.5 + If I multiply the 1.25 + 2i would get 2.5
:) Well, I dunno about anyone else but this question makes my head spin!
