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natka813 [3]
4 years ago
6

Find the center and radius of a circle defined by the equation x^2+yy^2+4x-8y+13=0

Mathematics
1 answer:
gogolik [260]4 years ago
8 0
Hello : 
x²+y²+4x-8y +13 = 0
(x² +4x) +(y² -8y )+13 = 0
(x²+4x+4) -4 +(y-8y +16) -16 +13 = 0
(x+2)² +(y -4)² = 7
the center is : (-2 , 4) and radius <span>√7</span>
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SOVA2 [1]

Answer:

the 3 sides of the triangle are 105 ft, 40 ft and 70 ft.

Step-by-step explanation:

the perimeter is the sum of the 3 sides of the triangle

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Answer:

1) Length of BC + Length of DE = 17 cm

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Step-by-step explanation:

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The length of the rectangular sheet of paper = 17 cm

The width of the rectangular sheet of paper = 12 cm

Therefore, we have;

The length of the side of the cut out square piece = DE = CD

By the definition of a square, the length of all sides of the square are equal

The length of BC + The length of one side of the square = The length of the rectangular paper = 17 cm

The length of BC + The length of one side of the square DE (or CD) = 17 cm

2) The perimeter, 'P', of the shape ABCDEF is given as follows;

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Therefore, we have;

P = Length of AB + Length of BC + Length of DE + Length of CD + Length of EF + Length of FA

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