Ask question

Ask question

All categories

3 years ago

12

PLZ help ASAP!!! leo is saving money to buy snowboard march he save $200 in April he saved 35% more than what he saved in March

how much did he save in April

1 answer:

sladkih [1.3K]3 years ago

4 0

$200/(0.35) = $70

$200 + $70 = $270

You might be interested in

Which of the following is equivalent to 0 equals 3 x squared minus 12 x minus 15 when completing the square?

skad [1K]

Answer:

x = 5, -1

Step-by-step explanation:

0 = 3x^2 - 12x - 15 or

3x^2 - 12x - 15 = 0

By solving for x, use the Quadratic Formula.

… x = 5 and/or -1

8 0

3 years ago

Liliana wants to determine the height of an enlarged photo that she plans to frame. The original photo was 11 inches wide by 14

inn [45]

Answer: 168 inches.

Explanation:

First thing you must always do when solving word problems is read closely, and take note of any number.

In this case, the first thing we must do is find the scale factor.

For this, we use one of the dimensions. We will use the width of the photo.

We have then:

k = 132/11

k = 12

Then, we look for the value of the height of the new photo. To do this, we multiply the scale factor by the original dimension.

We have then:

14k = 14 (12) = 168

Thus, 168 inches is your answer! :)

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

I will give brainiest to whoever answers correctly !!

evablogger [386]

Answer:

markup=62 %

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

3 years ago

Read 2 more answers

Use the method of Gauss-Jordan elimination (trails—forming (lie augmented matrix into reduced echelon form) to solveProblem in S

Nezavi [6.7K]

Answer:

Step-by-step explanation:

Answer is in below attachment

7 0

4 years ago