1/3 of 30 would be 10. So 10 students walk to school.
For this case we must solve the following equation:

If we apply cubic root to both sides of the equation, then we eliminate the exponent on the left side:
![\sqrt [3] {x ^ 3} = \sqrt [3] {22}\\x = \sqrt [3] {22}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7Bx%20%5E%203%7D%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%5C%5Cx%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D)
That is the exact solution of the equation. Its decimal solution is given by:
![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
ANswer:
The solution to the equation is ![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
Answer:
I dont understand ur question
a. 
b. 
c. 
Step-by-step explanation:
Step 1; First, we convert the given fractions into improper ones. To do this, we multiply the whole number with the denominator of the fraction and add with it the same fraction's numerator whereas the denominator remains unchanged. To convert the fraction
3
= (3 × 4) + 1 / 4 =
,
2
= (2 × 3) + 1 / 3 =
,
6
= (6 × 5) + 1 / 5 =
,
4
= (4 × 4) + 1 / 4 =
,
5
= (5 × 7) + 2 / 7 =
,
4
= (4 × 3) + 1 / 3 =
.
Step 2; Now we subtract, using LCM to arrive at the answer
3
- 2
=
-
=
=
,
6
- 4
=
-
=
=
,
5
- 4
=
-
=
=
.