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True [87]
3 years ago
6

A typist can type 3 pages in 20 minutes.How many pages can he type in an hour?

Mathematics
2 answers:
notka56 [123]3 years ago
6 0
An hour is 60 minutes, divide 60 by 20(that equals 3), then  multiply 3 by 3 to get the answer 9 pages.
bonufazy [111]3 years ago
3 0
9 pages because there are 3 pages for every 20 minutes so you add 20+20+20=60 which is an hour then add 3 each time you add 20 minutes
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A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca
Alecsey [184]

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

4 0
4 years ago
Diastolic blood pressures are assumed to follow a normal distribution with a mean of 85 and a standard deviation of 12. What pro
Bogdan [553]

Answer:

0.3745

Step-by-step explanation:

We have to solve the problem by calculating the z-score value that has the following formula:

z <(x - m) / sd

x is the value to evaluate (<80), m is the mean (85) and the standard deviation is sd (12)

replacing:

p (x <80) = z <(80 - 85) / 12

z <-0.416, we look for this value in the normal distribution table and it corresponds to:

p (x <80) = 0.3745

Which means that the proportion of people is 0.3745

7 0
3 years ago
What is the least common multiple of 5, 20, and 33?
Sholpan [36]

Answer:

The least common multiple of all of the terms is 60

7 0
4 years ago
Read 2 more answers
A squared minus 1/4 is 0. solve for a
Ludmilka [50]

Answer:

a=1/2

Step-by-step explanation:

first we need to isolate a squared. so we add 1/4 to both sides

then you take the square root of a square to get 1/2

to check, 1/2 * 1/2 = 1/4

1/4-1/4 = 0

8 0
4 years ago
Suppose the random variable x is best described by a normal distribution with μ=23 and σ=4. Find the z-score that corresponds to
Serga [27]

Answer:

a) Z = 2.25

b) Z = 1.50

c) Z = -1.75

d) Z = 3.25

e) Z = -2.25

f) Z = 3.50

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

In this problem, we have that:

\mu = 23, \sigma = 4

(a) x=32

z=

Z = \frac{X - \mu}{\sigma}

Z = \frac{32 - 23}{4}

Z = 2.25

(b) x=29

z=

Z = \frac{X - \mu}{\sigma}

Z = \frac{29 - 23}{4}

Z = 1.50

(c) x=16

z=

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 23}{4}

Z = -1.75

(d) x=36

z=

Z = \frac{X - \mu}{\sigma}

Z = \frac{36 - 23}{4}

Z = 3.25

(e) x=14

z=

Z = \frac{X - \mu}{\sigma}

Z = \frac{14 - 23}{4}

Z = -2.25

(f) x=37

z=

Z = \frac{X - \mu}{\sigma}

Z = \frac{37 - 23}{4}

Z = 3.50

4 0
3 years ago
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