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2 years ago

The GCF of 14 and 35 is _____. Numerical Answers Expected!

2 answers:

8 0

GCF is greatest common factor.
The factors of 14 are 1,2,7,14
The factors of 35 are 1,5,7,35.
The GCF they both share is 7.

____ [38]2 years ago

3 0

1. Find the factors for each number
The factors for 14 is 1, 2,7, and 14 and the factors for 35 is <span>1, 5, 7, 35.

2. Find the greatest factor that is in both list.
14- 35
1 1
2 5
7 7
35

The greatest factor of 14 and 35 is 7. </span>

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The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

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3 years ago

Please help! geometry probabilities

Sladkaya [172]

You have -4,-3,-2, that is a 3 out of a total of 21 points or numbers on the number line. 3/21 is reduces to 1/7.
3 goes into 21 , 7 times. That is why it reduces to 1/7.

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3 years ago

How many solutions exist for the following system of equations: 4x + y = 7 and 3x - y = 0 a. no solution b. one solution c. infi

Zanzabum

$4x+y=7 \\
\underline{3x-y=0} \\
4x+3x=7+0 \\
7x=7 \ \ \ |\div 7 \\
x=1 \\ \\
3x-y=0 \\
3 \times 1-y=0 \\
3-y=0 \ \ \ |+y \\
y=3 \\ \\
(x,y)=(1,3)$

The answer is B. one solution.

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3 years ago

PLEASE HELP!! BE AUICK AND EXPLAIN!Solve the system by graphing!

zubka84 [21]

The answer to the question is (2,-2) d

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wat factor is paired of 5 to give 45 wat factor is paired with 3 to give 24 wat factor is paired with 6 to give 54

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