The units for expressing electric field strength include:

1 answer:

3 0

I would most probably presume the units are newton and Coulombs, which is choice b. This is correct because when measuring electric field strength, force and coulomb's law should be observed. Thank you for your question. Please don't hesitate to ask in Brainly your queries.

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Starting at t = 0 a net external force in the +x-direction is applied to an object that has mass 5.00 kg. A graph of the force a

Reptile [31]

Answer:

15√2 N

Explanation:

The acceleration is given by ...

a = F/m = 5t/5 = t . . . . meters/second^2

The velocity is the integral of acceleration:

v = ∫a·dt = (1/2)t^2

This will be 9 m/s when ...

9 = (1/2)t^2

t = √18 . . . . seconds

And the force at that time is ...

F = 5(√18) = 15√2 . . . . newtons

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A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$