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2 years ago

How much work is required to move an electron

Physics

1 answer:

vodomira [7]2 years ago

5 0

Answer:

(2) the work required to move the electron is 4.8 x 10⁻¹⁹ J.

Explanation:

Given;

potential difference, V = 3.00 volts

charge of electron, q = 1.6 x 10⁻¹⁹ C

The work required to move an electron is calculated as;

W = Vq

where;

W is the work done in Joules

Substitute the given values and solve for W;

W = (3.00)(1.6 x 10⁻¹⁹)

W = 4.8 x 10⁻¹⁹ J.

Therefore, the work required to move the electron is 4.8 x 10⁻¹⁹ J.

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The kinetic energy K of a moving object varies jointly with its mass m and the square of its velocity v. If an object weighing 4

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Answer:

K' = 1777.777 J

Explanation:

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3 years ago

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A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in

Kryger [21]

The average power is $3.0\cdot 10^6 W$

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

$W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2$

where :

$K_f = \frac{1}{2}mv^2$ is the final kinetic energy of the car, with

m = 2000 kg is the mass of the car

v = 60 m/s is the final speed of the car

$K_i = \frac{1}{2}mu^2$ is the initial kinetic energy of the car, with

u = 30 m/s is initial speed of the car

Soolving:

$W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J$

Now we can find the power required for the acceleration, which is given by

$P=\frac{W}{t}$

where

t = 9 s is the time elapsed

Solving:

$P=\frac{2.7\cdot 10^6}{9}=3.0\cdot 10^6 W$

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

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ANSWER:

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