In a thermos bottle, the vacuum between two glass bottles prevents heat being conducted between the bottles. T or F

Physics

2 answers:

alisha [4.7K]3 years ago

7 0

Fouls hop that helped(:(:(:(:

Gala2k [10]3 years ago

5 0

the answer is true because do your own experiment..for example: if the inside of your home is warmer than the outside/ smoking a cigarette by an open window wen it's cold outside, you will notice the cigarette smoke comes back inside, that is because doing this creates the opposite wanted effect. the temperature difference from inside -outside causes the cold air to b drawn to the warmer air therefore creating this effect. similar to lower concentrations moving to higher concentrations with h2o..hope this helps, unless I misunderstood??

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An 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching th

ddd [48]

Answer:

1626.4 N

Explanation:

Given that a 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him?

The parameters to be considered are:

Distance S = 3m

Time t = 0.55s

Since the man started from rest, initial velocity u = 0

Using second equation of motion

S = Ut + 1/2at^2

3 = 1/2 × a × 0.55^2

3 = 1/2 × a × 0.3025

a = 3/ 0.15125

a = 19.83 m/s^2

Force = mass × acceleration

Force = 82 × 19.83

Force = 1626.4 N

Therefore, the force that water exerted on him is 1626.4 N

4 0

3 years ago

Hey guys can you help me solve this problem "how long will it take a car travelling 30m/s to come to stop ifs its acceleration i

salantis [7]

Answer:

10 seconds.

Explanation:

We can use a kinematic equation where we know the final velocity, initial velocity, acceleration, and need to determine the time t:

$\displaystyle v_f = v_i + at$

The initial velocit is 30 m/s, the final velocity is 0 m/s (as we stopped), and the acceleration is -3 m/s².

Substitute and solve for t:

$\displaystyle \begin{aligned} (0\text{ m/s}) & = (30 \text{ m/s}) + (-3 \text{ m/s$^2$}) t \\ \\ t & = \frac{-30\text{ m/s}}{-3 \text{ m/s$^2$}} \\ \\ & = 10 \text{ s} \end{aligned}$