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Murrr4er [49]
3 years ago
7

A comic-strip writer churns out different numbers of comic strips each day. The writer logged the number of comic strips he wrot

e each day for 16 days and sorted the data in ascending order to create this data set. {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 8} If the writer writes for two more days and creates 5 and 7 comic strips, respectively, the difference of the mean and the median for the new data set is?
Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0
1st Data set: <span>1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 8

mean: 3.5
median: 3

2nd Data set: </span><span>1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 7, 8

mean: 3.78
median: 3.5

difference in mean: 3.78 - 3.5 = 0.28
difference in median: 3.5 - 3 = 0.50</span>
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2 years ago
Find the value of yy in each equation. Explain how you determined the value of y.
Hitman42 [59]

Answer:

a) 3

b) 9

c) 81

d) x

Step-by-step explanation:

We know the properties of log function as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = \log(A)+\log(B)

3) log(aᵇ) = b × log(a)

also,

4) \log_b(a)=\frac{\log(a)}{\log(b)}

Given:

a. y = 3^{\log_3(3)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(3)})

using 3, we get

log(y) = log₃(3) × log(3)

using 4, we get

log(y) =  \frac{\log(3)}{\log(3)} × log(3)

or

log(y) =  1 × log(3)

taking anti-log both sides

y = 3

b. y = 3^{log_3(9)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(9)})

using 3, we get

log(y) = log₃(9) × log(3)

using 4, we get

log(y) =  \frac{\log(9)}{\log(3)} × log(3)

or

log(y) = log(9)

taking anti-log both sides

y = 9

c. y = 3^{\log_3(81)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(81)})

using 3, we get

log(y) = log₃(81) × log(3)

using 4, we get

log(y) =  \frac{\log(81)}{\log(3)} × log(3)

or

log(y) =  log(81)

taking anti-log both sides

y = 81

d. y = 3^{\log_3(x)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(x)})

using 3, we get

log(y) = log₃(x) × log(3)

using 4, we get

log(y) =  \frac{\log(x)}{\log(3)} × log(3)

or

log(y) =  log(x)

taking anti-log both sides

y = x

3 0
3 years ago
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