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mihalych1998 [28]
2 years ago
8

Eric has 130 coins consisting of nickels and quarters the coins combined value comes to 15.90

Mathematics
2 answers:
Afina-wow [57]2 years ago
6 0

Answer:

Quarters = 47

Nickels = 83

Step-by-step explanation:

A) N + Q = 130

B) .05N + .25Q = 15.90

Multiplying equation A by -.05 equals

A) -.05N -.05Q = -6.50  then adding this to B)

B) .05N + .25Q = 15.90  Equals

.20Q = 9.40

Quarters = 47

Nickels = 83

.05*83 + .25*47 = 4.15 + 11.75 = 15.90

just olya [345]2 years ago
3 0

Answer:

A) N + Q = 130

B) .05N + .25Q = 15.90

Multiplying equation A by -.05 equals

A) -.05N -.05Q = -6.50  then adding this to B)

B) .05N + .25Q = 15.90  Equals

.20Q = 9.40

Quarters = 47

Nickels = 83

.05*83 + .25*47 = 4.15 + 11.75 = 15.90

Step-by-step explanation:


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Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

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That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

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Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

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