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Ronch [10]
3 years ago
7

PLEASE HELP QUICK Suppose a particle is moving along the x-axis. The position, measured in feet, of the particle can be modeled

by the quadratic equation y = 3x2 − 12x − 9, where x is time, in seconds. What does the number −9 represent for the quadratic function? The particle is 9 feet to the left of the origin. The particle is moving left 9 feet per second. The particle is accelerating at −9 feet per second squared. The particle has stopped at 9 seconds.
Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0

The number -9 is the value of y, the position at time x=0. So that's -9 feet right of the origin, or 9 feet left of the origin, first choice.



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never [62]

Answer:

To find the answers, all I have to do is apply the operations (plus, minus, times, and divide) that they tell me to, in the order that they tell me to.

(f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6

(f – g)(x) = f (x) – g(x)

= [3x + 2] – [4 – 5x]

= 3x + 2 – 4 + 5x

= 3x + 5x + 2 – 4

= 8x – 2

(f  × g)(x) = [f (x)][g(x)]

= (3x + 2)(4 – 5x)

= 12x + 8 – 15x2 – 10x

= –15x2 + 2x + 8

\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(

g

f

​

)(x)=

g(x)

f(x)

​

= \small{\dfrac{3x+2}{4-5x}}=

4−5x

3x+2

​

My answer is the neat listing of each of my results, clearly labelled as to which is which.

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f  × g ) (x) = –15x2 + 2x + 8

\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}(

g

f

​

)(x)=

4−5x

3x+2

​

Step-by-step explanation:

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Step-by-step explanation:

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Anon25 [30]
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Can you please help?
yan [13]

Answer:

f = (9c/5) + 32

Step-by-step explanation:

im pretty sure maybe

8 0
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Find an equation of the line l that passes through the point (x, y) = (−9, 2) and satisfies the condition. the x-intercept of l
spayn [35]
-9(2)+4=-16 you do -9 times 2 which is -18 then you subtract that to 4 which you get -16. hope this helps!

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