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4 years ago

Which is the graph of 3x + 5y = -15

Mathematics

1 answer:

11111nata11111 [884]4 years ago

7 0

Answer: (Attached picture)

Step-by-step explanation:

Isolate y to form your equation, which is y = mx + b

3x + 5y = -15

3x + 5y -3x = -15 - 3x

5y = -15 - 3x

5y/5 = -15/5 - 3x/5

y = -3 - 3x/5

Rearrange: -3/5x -3 = y

Now graph: -3 is the y intersection and -3/5 is the slope.

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A school director must randomly select 6 teachers to part in a training session. There are 34 teachers at school. In how many di

prohojiy [21]

Answer:

Total possible ways to select 6 teachers from 34 teacher are $^{34}C_6=1344904$ .

Step-by-step explanation:

It is given that total number of teachers at a school is 34.

The school director must randomly select 6 teachers to part in a training session.

$^nC_r=\frac{n!}{r!(n-r)!}$

Where, n is total possible outcomes and r is number of selected outcomes.

Total teachers = 34

Selected teachers =6

Total number of possible ways to select 6 teachers from 34 teacher is

$^{34}C_6=\frac{34!}{6!(34-6)!}$

$^{34}C_6=\frac{34\times 33\times 32\times 31\times 29\times 28!}{6!(28)!}$

$^{34}C_6=1344904$

Therefore total possible ways to select 6 teachers from 34 teacher are $^{34}C_6=1344904$ .

7 0

3 years ago

Please ASAP. Find the value of u.

shusha [124]

Answer:

The answer is B 62

Step-by-step explanation:

I just divid 124 by 2

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4 years ago

Solve: m + 2/3 = 1/2 A. 1 1/6 B. 1/6 C. -1 D-1/6

xxMikexx [17]

I think the answer is (D).

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3 years ago

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The equation T^2=A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

Sergio039 [100]

The answer for your question is going to be. 2^((3)/(2)) I know this cause I just took a quiz with this question on it

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3 years ago

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HELP!!!

Jobisdone [24]

Answer:

$16$ is the number of quarters and $14$ is the number of dimes

Step-by-step explanation:

we know that

$1\ dime=\$0.10$

$1\ quarter=\$0.25$

Let

x-----> the number of dimes

y------> the number of quarters

we know that

$0.10x+0.25y=5.40$ -----> equation A

$x+y=30$ ----Isolate the variable y

$y=30-x$ -----> equation B

Substitute equation B in equation A

$0.10x+0.25(30-x)=5.40$

$0.10x+7.5-0.25x=5.40$

$0.25x-0.10x=7.5-5.40$

$0.15x=2.1$

$x=14\ dimes$

Find the value of y

$y=30-x$

$y=30-14=16\ quarters$

therefore

$16$ is the number of quarters and $14$ is the number of dimes

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3 years ago

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