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mr_godi [17]
3 years ago
13

Find the 12th term of the geometric sequence 8, 16, 32, ...

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0

Answer:

Step-by-step explanation:

\[a_{n}=a{1}r^{n-1}\]

r=16/8=2

a_{12}=8(2)^{12-1}

a_{12}=8(2)^{11}=16384  

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Wite a numerical expression for the below problems. Simplify the expressions.
ziro4ka [17]

Answer:

1) 9

2) 34

Step-by-step explanation:

For the first one, it would be

= (6×3)/2

= 18/2

= 9

The second one is,

= 36- (12/6)

= 36 - 2

= 34

4 0
2 years ago
A 28-year-old man pays $181 for a one-year life insurance policy with coverage of $150,000. If the probability that he will live
Marina CMI [18]
Expected value E(x) = 0.9994(150000 - 181) = 0.9994 x 149819 = $149,729.11
3 0
3 years ago
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8_murik_8 [283]

Answer:

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Step-by-step explanation:

4 0
3 years ago
A research study investigated differences between male and female students. Based on the study results, we can assume the popula
garri49 [273]

Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = 0.5.
  • Sample of 100, hence n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2 = \frac{X - 3.5}{0.05}

X - 3.5 = -0.1

X = 3.4

Z = 2:

Z = \frac{X - \mu}{s}

2 = \frac{X - 3.5}{0.05}

X - 3.5 = 0.1

X = 3.6

The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

7 0
2 years ago
SOS HELPPPP
Hunter-Best [27]

Answer:

18

Step-by-step explanation:

5 0
2 years ago
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