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3 years ago

Find the 12th term of the geometric sequence 8, 16, 32, ...

Mathematics

1 answer:

OLEGan [10]3 years ago

8 0

Answer:

Step-by-step explanation:

\[a_{n}=a{1}r^{n-1}\]

r=16/8=2

a_{12}=8(2)^{12-1}

$a_{12}=8(2)^{11}=16384$

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Simplify 2a+2−3a−5+a−4+7a.

zhuklara [117]

Answer:

7a-7

Step-by-step explanation:

2a+2−3a−5+a−4+7a.

Combine like terms

2a-3a+a+7a+2-5-4

7a-7

3 0

3 years ago

Read 2 more answers

Need answer to 4 and 5

algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3$ = 6

$g_3 = 2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9$ = 18

$g_4 = 2 . 3^{4 - 1} = 2 . 3^{3} = 2 . 27$ = 54

$g_5 = 2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81$ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $t_n = \frac{2}{3}t_{n - 1}$

$t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1 = \frac{2}{3}6$ = 4

$t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3}$

$t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9}$

$t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27}$

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0

3 years ago

A train travels at a constant speed of 35 feet per second. How many minutes will it take the train to travel exactly 70 miles? (

olga_2 [115]

176 minutes,

70x5,280= 369,600 divide by 35= 10,560 divide by 60=176

3 0

3 years ago

Read 2 more answers

Find the domain of the function. (Enter your answer using interval notation.)

Rudik [331]

All real numbers since there is no exclusions. (-inf, inf)

7 0

3 years ago

I need help with this!

Leviafan [203]

Solution

f(r) = 3.14 $r^{2}$

Now we have to find the area of the circle when the radius (r) = 4.

Plug in r = 4 in f(r) to get the area of the circle.

f(4) = 3.14 $(4^{2} )$

f(4) = 3.14 * 4 * 4

f(4) = 3.14 *16

f(4) = 50.24

The answer is C. 50.24

7 0

3 years ago