
Let's find out the gradient (Slope " m ") of line q ;



Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :


Now, plug in the value of gradient ~

here we can clearly observe that, the Area under the curve can easily be represented as :

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
Find the velocity first, the "slope".
m=(y2-y1)/(x2-x1)
m=(95.5-53)/(4-2)
m=21.25 ? Your equations are wrong, I'll double check with another set of points...
m=(350.5-308)/(16-14)
m=21.25 LOL, yep none of your lines has the correct slope.
Anyway...
y=21.25x+b, using any point we can solve for the y-intercept, or "b", (2, 53)
53=21.25(2)+b
53=42.5+b
10.5=b so the distance to the lighthouse as a function of time is:
y=21.25x+10.5
So essentially, you should fire your teacher or burn that book you are using :)
Answer: 0.6 in 10 % ; 0.4 in 15 %
Step-by-step explanation:
1. (x*10%) + (y*15%)/ x+y=12%
2. x+y = 1 x= 1-y
(0.1x + 0.15y/ x+y= 12/100) * 100
(10x + 15y/x+y = 12)*(x+y)
10x+15y= 12x + 12y
-2x=-3y
2x = 3y 2(1 - y)= 3y
2-2y=3y 2= 5y
y= 0.4
x= 0.6
Answer:

Step-by-step explanation:
Answer:
I cant read the handwriting sorry
Step-by-step explanation: