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pantera1 [17]
3 years ago
15

Yvonne was asked to construct a line through P that is perpendicular to the given line segment AB for homework.

Mathematics
1 answer:
Oxana [17]3 years ago
6 0

Answer: C

Step-by-step explanation:

Place the compass on point and mark an arc above AB that goes through P, and a similar arc below AB.

I just did the CYU and this was correct

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Two paper drink cups are shaped like cones. The small cone can hold 6 oz of water. The large cone is 4/3 the height and 4/3 the
dolphi86 [110]
The answer you’re looking for is c 4.5 oz
5 0
2 years ago
Use the figure below and 2-3 sentences to explain the following:
nydimaria [60]

Answer:

See below

Step-by-step explanation:

The side opposite angle E is side e (DF)

The side adjacent to angle E is side d (EF)

The hypotenuse is side f (ED)

5 0
3 years ago
I need help with this problem
Anit [1.1K]

Answer:

show how you know  .. :D  good rhyme  

Step-by-step explanation:

park = 4" x 6"    ( inches)  small park

but one inch = 30 miles  ooh big park

4*30 X 6*30

120 X 180  miles... like a big game range?  :?  very big

since we only have 6 square inches to fit the map into... then.. what size of map would fit?    what size equals 6 inches?    2 x 3 ?  hmm yes that's 6

soooo  shrink the 4" x 6" to  2"x 3" so the scale needs to double or

1 inch = 60 miles

2"*60  x 3"*60 = 120 x 180 miles.. looks good   try that :)

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!<br><br> Subract and simplify.
pantera1 [17]

Answer: C

<u>Step-by-step explanation:</u>

  \dfrac{x+1}{x-5} - \dfrac{x-2}{x+3}

= \dfrac{x+1}{x-5}(\dfrac{x+3}{x+3}) - \dfrac{x-2}{x+3}(\dfrac{x-5}{x-5})

= \dfrac{x^{2}+4x+3}{(x-5)(x+3)} - \dfrac{x^{2}-7x+10}{(x-5)(x+3)}

= \dfrac{x^{2}+4x+3-(x^{2}-7x+10)}{(x-5)(x+3)}

= \dfrac{11x-7}{(x-5)(x+3)}

5 0
3 years ago
I can’t find the area
evablogger [386]
Divide it into chunks of area you can find. One way to divide it is
.. a rectangle 2 mi x 5 mi at upper left.
.. a rectangle 8 mi x 6 mi down the middle
.. a rectangle 3 mi x 4 mi at lower right
.. a triangle 5 mi x 6 mi at lower left

Then the sum of areas is
.. (2 mi)*(5 mi) +(8 mi)*(6 mi) +(3 mi)*(4 mi) + (1/2)*(5 mi)*(6 mi)
.. = 10 mi^2 +48 mi^2 +12 mi^2 +15 mi^2
.. = 85 mi^2
4 0
3 years ago
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