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Lelechka [254]
4 years ago
12

For the reaction MgSO3(s) → MgO(s) + SO2(g), which is spontaneous only at high temperatures, one would predict thata. ΔH˚ is neg

ative and ΔS˚ is negativeb. ΔH˚ is positive and b. ΔS˚ is negativec. ΔH˚ is positive and ΔS˚ is positived. ΔH˚ is negative and ΔS˚ is positive
Chemistry
1 answer:
Nataliya [291]4 years ago
8 0

Answer: c. ΔH˚ is positive and ΔS˚ is positive

Explanation:

According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy  

\Delta H = enthalpy change

\Delta S = entropy change  

T = temperature in Kelvin

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Thus for \Delta G=-ve

Case :

T\Delta S > \Delta H

when \Delta S\text{ and }\Delta H both have positive values.

\Delta G=(+ve)-T(+ve)

\Delta G=(+ve)(-ve)=-ve

Reaction is spontaneous only at at high temperatures.

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A compound made of two elements, iridium (Ir) and oxygen (O), was produced in a lab by heating iridium while exposed to air. The
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1) Compund Ir (x) O(y)

2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g

3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g

4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g

5) Convert grams to moles

moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles

moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131

6) Find the proportion of moles

Divide by the least of the number of moles, i.e. 0.00656

Ir: 0.00656 / 0.00656 = 1

O: 0.0131 / 0.00656 = 2

=> Empirical formula = Ir O2 (where 2 is the superscript for O)

Answer: Ir O2
5 0
4 years ago
Read 2 more answers
Starting with a 6.847 M stock solution of HNO3, five standard solutions are prepared via serial dilution. At each stage, 25.00 m
stiks02 [169]

Answer: The concentration of HNO_3 in the final solution is 0.006688 M and number of moles are 0.00006688

Explanation:

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 6.847 M

V_1 = volume of stock  solution = 25.00 ml

M_2 = molarity of ist dilute solution = ?

V_2 = volume of first dilute solution = 100.0 ml

6.847\times 25.00=M_2\times 100.0

M_2=1.712M

2) on second dilution;

1.712\times 25.00=M_2\times 100.0

M_2=0.4280M

3) on third dilution

0.4280\times 25.00=M_2\times 100.0

M_2=0.1070M

4) on fourth dilution

0.1070\times 25.00=M_2\times 100.0

M_2=0.02675M

5) on fifth dilution

0.02675\times 25.00=M_2\times 100.0

M_2=0.006688M

Thus the concentration of HNO_3 in the final solution is 0.006688 M

moles of HNO_3 = Molarity\times {\text {Volume in L}}=0.006688\times 0.01L=0.00006688moles

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differences:  A plant cell contains a large, singular vacuole that is used for storage and maintaining the shape of the cell. In contrast, animal cells have many, smaller vacuoles. Plant cells have a cell wall, as well as a cell membrane. ... Animal cells simply have a cell membrane, but no cell wall.

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Why are mitochondria called the powerhouses of cells
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